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PHP Code:
![]() Whats the problem here ?Regards - miSt Show Your Support
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#2
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#3
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The idea was i did this on my own
![]() - miSt |
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#4
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aH, you should of said so from the begining :-p
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#5
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Yes so has anyone a solution to this - this is obviously more than just whats there
![]() - miSt |
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#6
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Im sorry but that seems right.
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#7
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Yes it is right - no parse errors or anything but it simple does not pull the image with the $banner variable for some reason
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#8
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hmm i dont know much php but i would guess maybe something to do with the do switch ? or the way your setting up the last $banner variable ? i dunno, thats what i would say but my knowledge lies in truebasic or yabasic not php
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#9
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Try:
PHP Code:
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#10
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No parse erros with that code but again i hae $banner in my footer and it's not showing the image
![]() - miSt |
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