The Arcive of Official vBulletin Modifications Site.It is not a VB3 engine, just a parsed copy! |
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#1
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Show Guest Location for Administrator
I have guest access turned off on my board. and I don't show guests in "Who's Online". Is it possible to show a full who's online with guests and their location in the admin cp. I always see there are guests online and I am curious where they are on my website.
If anyone has some insite on this It would be greatly apreciated. thanks |
#2
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Quote:
Just enable the setting via Admin CP and you should be fine.. |
#3
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what I am looking for is it to show the guests only inside the admin cp and not the regular who's online.
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#4
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Let me give you another solution:
Edit online.php, find: PHP Code:
PHP Code:
Fits to you? |
#5
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I seem to get this error when i click on to see whos online
Parse error: parse error, unexpected '=' in /forums/online.php on line 622 |
#6
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sorry missing char.. Try now..
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#7
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still no goes.
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#8
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Can you please post the lines between 618 to 630 and tell me which one is 622?
Also make sure you use Notepad to edit and IE or Netscape (not Opera) to copy paste from here |
#9
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618:
return $userinfo; } 622: $allusers= $DB_site->query("SELECT user.username, session.location, session.lastactivity, user.userid, user.usergroupid, user.invisible, session.host, user.showemail, user.receivepm FROM session ". iif($WOLguests, " LEFT JOIN user USING (userid) ", ",user") ." WHERE session.lastactivity > $datecut ". iif(!$WOLguests, " AND session.userid = user.userid", "") ." ORDER BY user.username "); $moderators = $DB_site->query("SELECT DISTINCT userid FROM moderator"); |
#10
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And where is the hack code I told you to insert?
It seems that you are getting the error BEFORE applying the hack.. Quote:
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X vBulletin 3.8.12 by vBS Debug Information | |
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More Information | |
Template Usage:
Phrase Groups Available:
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Included Files:
Hooks Called:
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