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  #1  
Old 10-04-2002, 04:48 PM
exTracT exTracT is offline
 
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Default Show Guest Location for Administrator

I have guest access turned off on my board. and I don't show guests in "Who's Online". Is it possible to show a full who's online with guests and their location in the admin cp. I always see there are guests online and I am curious where they are on my website.

If anyone has some insite on this It would be greatly apreciated.

thanks
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  #2  
Old 10-04-2002, 07:29 PM
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Quote:
Originally posted by exTracT
I don't show guests in "Who's Online". Is it possible to show a full who's online with guests and their location in the admin cp.
I dont understand. Why did you disable "Guest activity on Who's Online" setting while this is exactly what you want?

Just enable the setting via Admin CP and you should be fine..
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  #3  
Old 10-04-2002, 08:46 PM
exTracT exTracT is offline
 
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what I am looking for is it to show the guests only inside the admin cp and not the regular who's online.
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  #4  
Old 10-04-2002, 09:07 PM
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Let me give you another solution:

Edit online.php, find:
PHP Code:
  default:
    
$userinfo[activity] = 'unknown';
  }

  return 
$userinfo;

After that add:
PHP Code:
if ($bbuserinfo[usergroupid]==6)
{
$WOLguests=1;} 
This will display the guests to only Site Admins in who is online..

Fits to you?
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  #5  
Old 10-04-2002, 10:53 PM
exTracT exTracT is offline
 
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I seem to get this error when i click on to see whos online

Parse error: parse error, unexpected '=' in /forums/online.php on line 622
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  #6  
Old 10-05-2002, 07:06 AM
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sorry missing char.. Try now..
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  #7  
Old 10-05-2002, 07:30 AM
exTracT exTracT is offline
 
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still no goes.
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  #8  
Old 10-05-2002, 07:37 AM
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Can you please post the lines between 618 to 630 and tell me which one is 622?

Also make sure you use Notepad to edit and IE or Netscape (not Opera) to copy paste from here
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  #9  
Old 10-05-2002, 07:39 AM
exTracT exTracT is offline
 
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618:
return $userinfo;
}

622: $allusers= $DB_site->query("SELECT user.username, session.location, session.lastactivity, user.userid, user.usergroupid, user.invisible, session.host, user.showemail, user.receivepm
FROM session
". iif($WOLguests, " LEFT JOIN user USING (userid) ", ",user") ."
WHERE session.lastactivity > $datecut
". iif(!$WOLguests, " AND session.userid = user.userid", "") ."
ORDER BY user.username
");

$moderators = $DB_site->query("SELECT DISTINCT userid FROM moderator");
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  #10  
Old 10-05-2002, 07:54 AM
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And where is the hack code I told you to insert?

It seems that you are getting the error BEFORE applying the hack..

Quote:
Originally posted by exTracT
618:
return $userinfo;
}

622: $allusers= $DB_site->query("SELECT user.username, session.location, session.lastactivity, user.userid, user.usergroupid, user.invisible, session.host, user.showemail, user.receivepm
FROM session
". iif($WOLguests, " LEFT JOIN user USING (userid) ", ",user") ."
WHERE session.lastactivity > $datecut
". iif(!$WOLguests, " AND session.userid = user.userid", "") ."
ORDER BY user.username
");

$moderators = $DB_site->query("SELECT DISTINCT userid FROM moderator");
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