I need this overgrow hack!!

I need this!!
I have tried contacting overgrow, but no response! Anybody know how to do this:

A lot of you know this is easy and you can do it in 5 minutes, so speak up!

what do I have to do for a little help!

[Steve Machol]

It sounds like Overgrow doesn't want to share this hack with you. Perhaps you should just respect that and move on.

Just a thought!

[Projektil]

..but i think it is relativly easy to find out how many members have been online today:

PHP Code:

$startTime ==  mktime (0, 0, 0, getdate('month'), getdate('mday'), getdate('year')  )
$endTime == mktime (23, 59, 59, getdate('month'), getdate('mday'), getdate('year')  )
mysql_query("SELECT * FROM user WHERE lastactivity>$startTime AND lastactivity<$endTime "); 


this should give you the number of users. i never tested it but you might want to start to build the hack for us.

Originally posted by smachol
It sounds like Overgrow doesn't want to share this hack with you. Perhaps you should just respect that and move on.

Just a thought!

actually I contacted overgrow and he gave me a few people to IM and ask, he said as soon as he upgrades to VB version 2.0 he will give me the hack

Originally posted by projektil
..but i think it is relativly easy to find out how many members have been online today:

PHP Code:

$startTime ==  mktime (0, 0, 0, getdate('month'), getdate('mday'), getdate('year')  )
$endTime == mktime (23, 59, 59, getdate('month'), getdate('mday'), getdate('year')  )
mysql_query("SELECT * FROM user WHERE lastactivity>$startTime AND lastactivity<$endTime "); 


this should give you the number of users. i never tested it but you might want to start to build the hack for us.

I am trying to get a hack that will tell me the time of day highest number of users that were on during the day, get what I mean?

come on people!!

hello?

[Dark_Wizard]

This type of persistence will get you no where, just be patient....