The Arcive of Official vBulletin Modifications Site.It is not a VB3 engine, just a parsed copy! |
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#1
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site hacked - no cp access
Running an earlier version of 3.7 and it looks like i've been hit with a redirect hack. Cannot log into the admin CP either. I've done a preliminary search on the subject and have tried a few things to no avail. Anyone have an idea of the best way to fix this? I'd be willing to pay through paypal if necessary. Web host is playing dumb. Any help would be greatly appreciated.
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#2
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try backup of your database.
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#3
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Before you do that... You do have access to the database, correct? If not phpMyAdmin, you at LEAST have the database password, yes?
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#4
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yes, i do have access to the database in my fantastico control panel but i dont see a lot of options there.
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#5
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Sorry for the late response, I'm sure you've already figured out what to do by now... But I'll post in case other experience a similar problem.
I've never used Fantastico, but if it allows you to manipulate the database, get somewhere where you can enter a MySQL Command. First enter this: Code:
SELECT username, userid FROM user WHERE usergroupid=6 OR FIND_IN_SET(6, membergroupids) First find out if there's anything in your membergroupids: Code:
SELECT membergroupids FROM user WHERE userid=YOURUSERIDHERE Code:
UPDATE user SET membergroupids=CONCAT(membergroupids, ',6') WHERE userid=YOURUSERIDHERE Code:
UPDATE user SET membergroupids='6' WHERE userid=YOURUSERIDHERE If you are ALREADY in the Admin group, then it means the Admin Group was changed to not be Admins anymore, or something. XP If that's the case, use this code to make the group Administrator again: Code:
UPDATE usergroup SET adminpermissions=3 WHERE usergroupid=6 Code:
UPDATE administrator SET adminpermissions=491516 WHERE userid=YOURUSERIDHERE ***: Note, this might vary depending on if you've added bitfields. I -think- this is default, but not sure. You can check who has what permissions, though, by using Code:
SELECT administrator.userid, administrator.adminpermissions, user.username FROM administrator, user WHERE administrator.userid=user.userid |
#6
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essque,
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