Convert template conditional into plugin code

[Mark.B]

Hi

I have the following template conditional, variants upon which I use quite a lot:

<if condition="!in_array($foruminfo['forumid'], array(1,2,3,4))">

I can work out how to format most conditionals if they are needed in php plugin code rather than in a template. However, I am unsure how to do this for the in_array stuff.

How would I format the above conditional to make it apply to a block of plugin code? (Assuming it's at a hook where $foruminfo is available).

[Lynne]

Actually, that one if pretty much the same in php:

if (!in_array($foruminfo['forumid'], array(1,2,3,4)))

(Sometimes you need to change $foruminfo to $forum or $thread or $threadinfo, depending. Sometimes you can even just use $forumid instead of $foruminfo['forumid'])

[Mark.B]

Thanks Lynne....I needed that as previously I was using something like

if ($forum['forumid'] != 1 AND $forum['forumid'] != 2 AND $forum['forumid'] != 3 AND $forum['forumid'] != 4)

Not sure if that's the exact syntax as I've just typed it from memory, I've deleted it now. But you get the idea.

It was working but I felt it was ridiculously long winded, and I had read somewhere it used marginally more resources doing it that way.

[Dismounted]

Originally Posted by Mark.B

It was working but I felt it was ridiculously long winded, and I had read somewhere it used marginally more resources doing it that way.

The difference would be negligible, unless you're processing a lot of comparisons.