Syntax Question: "->"

[citricguy]

Ok, for the most part I understand this, but what exactly does the '->' do (in the code below)? I have had some trouble searching for it due to the length and charactors used :ermm:

PHP Code:

// Question about this code:
if ($a== '' OR !$b->options['somthing']) 


[filburt1]

It references a field or method in an object. In this case, index "somthing" in the field "options" in the object "b."

http://www.php.net/oop

[citricguy]

http://www.php.net/oop definatly helped, (Thank you!)

PHP Code:

if($b->options['somthing']) {
} 


So from that statement above...

• '$b' is an entity in and of itself (a class?)
• 'options['somthing']' is defined within the object $b?
• the proper way to reference 'options['somthing']' outside of the object '$b' is to use '$b->options['somthing']'?

[filburt1]

• $b is an object, which is an instance of a class. PHP doesn't have strong data types so there's no way of knowing by just looking at the code.
• options is an array in $b, and you're referencing the key "somthing".
• Yes, and inside the class, you have to use $this due to crappy scoping.

PHP has a broken, half-assed-implemented OOP model. If you really want to learn how OOP works, Java is the way to go.

[citricguy]

Hey thanks for taking the time to help me through that. Looks like im gona take a crack at Java next.