PHP question. Please take a look and see if you can help

[kjhkjh]

KirbyDE has really helped me out and we got to this point:

<?php
$username="dbusername";
$password="dbpassword";
$database="dbname";

mysql_connect('localhost',$username,$password);
@mysql_select_db($database) or die( "Unable to select database");

$randgetq=mysql_query("SELECT * FROM tablename ORDER BY RAND() LIMIT 1");

if (!$randgetresults=mysql_fetch_array($randgetq, MYSQL_ASSOC))
{
echo "Sorry no entries";
}
else
{
print_r($randgetresults);
}
mysql_close();
?>

It is almost perfectly

The small thing is that on the website when it prints the random entry from the table, it is also prints part of the code in the print output - ie/ it prints "array ( [tablefield] => 5456 )" when I just want it to print "5456" or any other random entry from the table)

Do you know why this might be or how I can stop it and just have the field entry printed?

My vB version is 3.0.8