Authorities Online

Requested by Austin Dea.

Just download the attached file and look at it. It contains complete instructions. This one is a no-brainer and should work for any 2.2.x version of vBulletin.

If you can't handle installing this hack, I'm not sure you're ready for hacks as it is extremely simple.

As usual no PMs, no ICQ, no AIM, no emails about this hack. They will go ignored.

:bunny: :bunny:

(I am including that bunny cause I really like it )

Edit: I realized I should probably explain what this does. It adds a seperate box below the Who's Online on forumhome that lists the admins/mods who are online.

[dreamhost]

great hack, is it possible to have it say admins, super moderators, moderators etc, with listing after each?

[Heineken77]

http://nba2k3.net/forum/index.php?s=

For some reason the Authorities is showing the correct users that it's supposed to, but next to "Authorities:" even when there are more than 1 mod/admin online it always says 0

What am I doing wrong Would really appreciate some advice.

[Heineken77]

Anyone have any guesses as to why my Authorities field reads 0 when there are infact Authorities online?

[lifesourcerec]

I want to be able to add more groups. It just adds admin and not moderators.

[lifesourcerec]

This is somewhat odd. I couldn't find the lines, but manually searching, this looks different.

Here is what the hack has listed:

PHP Code:

$leader = 0;
      if ($loggedin['usergroupid'] == 6 and $highlightadmin) {
        $username = "<b><i>$loggedin[username]</i></b>";
        $leader++; $lead = 1;
      } else if (($mod["$userid"] or $loggedin['usergroupid'] == 5) and $highlightadmin) {
        $username = "<b>$loggedin[username]</b>";
        $leader++; $lead = 1;
      } else {
        $username = $loggedin['username'];
        $lead = 0;
      }
      eval("\$activeusers .= \", ".gettemplate('forumhome_loggedinuser')."\";");
      if ($lead == 1) {
        eval ("\$leaders .= \", ".gettemplate('forumhome_loggedinuser_leader')."\";");
      } 


But here is what's in my file:

PHP Code:

$leader = 0;
      if ($loggedin['usergroupid'] == 6) {
          $username = "$loggedin[username]";
        $leaders2++; 
        $lead = 1;
      } else if ($loggedin['usergroupid'] == 7 or $loggedin['usergroupid'] == 5) {
          $username = "$loggedin[username]";
        $leaders2++; 
        $lead = 1;
      } else {
        $username = $loggedin['username'];
        $lead = 0;
      }
      eval("\$activeusers = \", ".gettemplate('forumhome_loggedinuser')."\";");
      if ($lead == 1) {
        eval ("\$leaders .= \"".gettemplate('forumhome_loggedinuser_leader')."\";");
      } 


Both are different. Should I replace the current to what's in the hack?

[lifesourcerec]

Never mind. I just basically combined the 2 and it works great

[StevenTN]

you don't need to do the leader2 variable... in fact the $leader = 0 is totally unneeded. I got mine to display the correct # of staff by getting rid of it.

[LOD-squa]

I'm getting this error:
Parse error: parse error, unexpected $ in /home/lod-squa/public_html/forum/index.php on line 454

can anyone help me?

[StevenTN]

Question... what do I do about the leading comma for the first mod or admin in leaders online... it'll show

", Steven, ..."

However, if the admin or mod is the first member listed in members online, that comma doesn't show. Can anyone help to solve it?

The boards are at http://www.thrillnetwork.com/boards/ if you wish to see what I'm talking about.

[dimava]

Originally posted by StevenTN
Question... what do I do about the leading comma for the first mod or admin in leaders online... it'll show

", Steven, ..."

However, if the admin or mod is the first member listed in members online, that comma doesn't show. Can anyone help to solve it?

The boards are at http://www.thrillnetwork.com/boards/ if you wish to see what I'm talking about.

same problem here


thanks,


Dimava