Code to display two images help!

[TigerC10]

Originally Posted by MarkFoster

That makes it so that no images are displayed, just one of those classic broken image boxes. Could it be releated to other parts of the code?

Well, yeah. You would have to go and alter the Javascript code to change all references from...

theImages[i]

to...

theImagesA[i]
theImagesB[i]

Where i is the number of the image.


I figured you would know to do that since you're changing a variable name there. It's not like you can alter 1 line of code and magically get everything to do everything you want.


EDIT:

Consider using this instead

<SCRIPT LANGUAGE="JavaScript">
 
<!-- Begin Random Logo In Header Script
 
var theImagesA = new Array() // do not change this
var theImagesB = new Array() // do not change this
 
<!-- Edit the url images to match yours
theImagesA[0] = 'images/statusicon/forum_old1.gif'
theImagesB[0] = 'images/statusicon/forum_old2.gif'
theImagesA[1] = 'images/statusicon/forum_new1.gif'
theImagesB[1] = 'images/statusicon/forum_new2.gif'
 
 
 
var j = 0
var p = theImagesA.length;
var preBufferA = new Array()
var preBufferB = new Array()
for (i = 0; i < p; i++){
preBufferA[i] = new Image()
preBufferA[i].src = theImagesA[i]
preBufferB[i] = new Image()
preBufferB[i].src = theImagesB[i]
}
var whichImage = Math.round(Math.random()*(p-1));
function showImage(){
document.write('<td align="$stylevar[left]"><a href="index.php"><img src="'+theImagesA[whichImage]+'" border="0" alt="$vboptions[bbtitle]" /><img src="'+theImagesB[whichImage]+'" border="0" alt="$vboptions[bbtitle]" /></a></div>');
}
 
// End -->
</script>

See? You have to do it to the whole thing.