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  #1  
Old 10-26-2005, 03:33 AM
CommuneZoom CommuneZoom is offline
 
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Default Simplying a few MySQL Queries - Help Needed

I have the following queries that, if possible, I need to simplify. I'd like to knock this down to as few queries as possible as I will need to call additional (probably 2 other items) from the same row.

I am just looking to get the number of rows matching each set, though I'd rather knock 4 queries down to 1-2 if there is another way to do so.

PHP Code:
$getpending $db->query_read("SELECT * FROM son_customers WHERE ispending = '1'");
$totalpending $db->num_rows($getpending);

$getactive $db->query_read("SELECT * FROM son_customers WHERE ispending = '0'");
$totalactive $db->num_rows($getactive); 
Is there an alternative, of will I be stuck making 4 seperate calls?
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  #2  
Old 10-26-2005, 03:48 AM
Guest190829
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Try the below, maybe it will work. I need to start coding php more, and stop with vb.net. I'm starting to forget stuff!

PHP Code:
 $getcustomers $db->query_read("SELECT COUNT(*) FROM son_customers");
 WHILE (
$result $db->fetch_array($getcustomers))
{
    if (
$result[ispending] == '0')
    {
        
$totalpending $totalpending 1
    
}
    else
    {
        
$totalactive $totalactive 1
    
}

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  #3  
Old 10-26-2005, 04:09 AM
CommuneZoom CommuneZoom is offline
 
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Default

Quote:
Originally Posted by Danny.VBT
Try the below, maybe it will work. I need to start coding php more, and stop with vb.net. I'm starting to forget stuff!

PHP Code:
 $getcustomers $db->query_read("SELECT COUNT(*) FROM son_customers");
 WHILE (
$result $db->fetch_array($getcustomers))
{
    if (
$result[ispending] == '0')
    {
        
$totalpending $totalpending 1
    
}
    else
    {
        
$totalactive $totalactive 1
    
}

Thanks for the reply, however, I need them both to be showing at the same time and not alternating.

As I need it to report the total for the entire table, the above will not work. I have 8 entries in the table and the above reports a blank for active and 1 for pending (when all 8 are pending).
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  #4  
Old 10-26-2005, 04:12 AM
Guest190829
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Quote:
Originally Posted by CommuneZoom
Thanks for the reply, however, I need them both to be showing at the same time and not alternating.

As I need it to report the total for the entire table, the above will not work. I have 8 entries in the table and the above reports a blank for active and 1 for pending (when all 8 are pending).
Try it without the Count clause. So...

PHP Code:
 $getcustomers $db->query_read("SELECT * FROM son_customers");
 WHILE (
$result $db->fetch_array($getcustomers))
{
    if (
$result[ispending] == '0')
    {
        
$totalpending $totalpending 1
    
}
    else
    {
        
$totalactive $totalactive 1
    
}

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  #5  
Old 10-26-2005, 06:02 AM
Paul M's Avatar
Paul M Paul M is offline
 
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Default

I think the logic may be backwards in that, totalactive should be when ispending = 0.

Try ;

PHP Code:
$getcustomers $db->query_read("SELECT ispending FROM son_customers"); 
 WHILE (
$result $db->fetch_array($getcustomers)) 

    if (
$result[ispending]) 
    { 
        
$totalpending += 
    

    else 
    { 
        
$totalactive += 
    


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  #6  
Old 10-26-2005, 12:43 PM
Marco van Herwaarden Marco van Herwaarden is offline
 
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PHP Code:
$getcustomers $db->query_first("SELECT SUM(IF(ispending = 1, 1, 0)) as pending,  SUM(IF(ispending = 0, 1, 0)) as active FROM son_customers"); 
finished.
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  #7  
Old 10-26-2005, 04:53 PM
Guest190829
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Can you explain this bit?

[sql]IF(ispending = 1, 1, 0)) [/sql]

I've never seen this before...
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  #8  
Old 10-26-2005, 05:43 PM
Marco van Herwaarden Marco van Herwaarden is offline
 
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if the value of ispending is '1', it will result in a value of 1, otherwise 0 (zero), if you then sum it, you will count 1 for each row that have ispending = 1.

By testing ispending = 0, you can reverse the count.
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  #9  
Old 10-26-2005, 05:50 PM
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Paul M Paul M is offline
 
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Quote:
Originally Posted by MarcoH64
PHP Code:
$getcustomers $db->query_first("SELECT SUM(IF(ispending = 1, 1, 0)) as pending,  SUM(IF(ispending = 0, 1, 0)) as active FROM son_customers"); 
finished.
Interesting question, is it quicker to use a more complicated SQL query, or a simpler query and a bit of PHP.
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  #10  
Old 10-26-2005, 08:48 PM
Marco van Herwaarden Marco van Herwaarden is offline
 
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Default

That depends totally on the query. Since this one are simple embedded functions, not used in where/order by/join conditions, i would say the query is much faster then doing it in php.
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