Query question - PLEASE HELP!!!

[Lea Verou]

I really need a hack that displays the average age. Currently I am using this plugin:

PHP Code:

$age_result=$db->query_first("SELECT ROUND(YEAR(NOW())-AVG(YEAR(birthday_search)),0) AS avgage FROM " . TABLE_PREFIX . "user WHERE YEAR(birthday_search) <> 0;");
$avg_age=$age_result['avgage']; 


but as you can see, it's not accurate as it only counts the year of the birthday and the current year...

Andreas/KirbyDE had given me this query instead that is supposed to be more accurate:

[sql]
SELECT ROUND(AVG(YEAR(NOW())-YEAR(birthday_search) - (MONTH(NOW()) < MONTH(birthday_search)) - (MONTH(NOW()) = MONTH(birthday_search) AND DAY(NOW()) < DAY(birthday_search)))) AS avgage FROM " . TABLE_PREFIX . "user WHERE YEAR(birthday_search)>0
[/sql]

but it gives a database error:

Database error in vBulletin 3.5.0:

Invalid SQL:
SELECT ROUND(AVG(YEAR(NOW())-YEAR(birthday_search) - (MONTH(NOW()) < MONTH(birthday_search)) - (MONTH(NOW()) = MONTH(birthday_search) AND DAY(NOW()) < DAY(birthday_search)))) AS avgage FROM testvb_user WHERE YEAR(birthday_search)>0;

MySQL Error  : You have an error in your SQL syntax.  Check the manual that corresponds to your MySQL server version for the right syntax to use near '(NOW()) < DAY(birthday_search)))) AS avgage FROM testvb_user WH
Error Number : 1064

Any ideas please? :nervous: