Query question - PLEASE HELP!!!
 

I really need a hack that displays the average age. Currently I am using this plugin:

but as you can see, it's not accurate as it only counts the year of the birthday and the current year...

Andreas/KirbyDE had given me this query instead that is supposed to be more accurate:

[sql]
SELECT ROUND(AVG(YEAR(NOW())-YEAR(birthday_search) - (MONTH(NOW()) < MONTH(birthday_search)) - (MONTH(NOW()) = MONTH(birthday_search) AND DAY(NOW()) < DAY(birthday_search)))) AS avgage FROM " . TABLE_PREFIX . "user WHERE YEAR(birthday_search)>0
[/sql]

but it gives a database error:
Any ideas please? :nervous:

try that query

[sql]
SELECT ROUND(AVG(YEAR(NOW()) - YEAR(birthday_search) - (DAYOFYEAR(birthday_search) - DAYOFYEAR(NOW())) / 365 AS avgage
FROM testvb_user
WHERE YEAR(birthday_search)>0;[/sql]

Thanks so much but I still get a db error... :(

Database error in vBulletin 3.5.0:
This is how I put it in the plugin:

Add a ')' in front of the AS avgage.

:( :( :(
I have started to think that it will never work out... :( :( :(

it's just a problem with brackets ;)

[sql]SELECT ROUND(AVG(YEAR(NOW()) - YEAR(birthday_search) - (DAYOFYEAR(birthday_search) - DAYOFYEAR(NOW()) / 365))) AS avgage
FROM testvb_user
WHERE YEAR(birthday_search)>0;[/sql]

Now there is no database error (woo hoo!! :D) but...
Average Age: -150 :(

very young users you have ;)

my fault, try that:

[sql]SELECT ROUND(AVG(YEAR(NOW()) - YEAR(birthday_search) - (DAYOFYEAR(birthday_search) - DAYOFYEAR(NOW())) / 365)) AS avgage
FROM testvb_user
WHERE YEAR(birthday_search)>0;[/sql]

It looks correct, thanks so much!!!!!! :D :D :D

Another question, not so urgent, answer if and when you have time... How can I make it to display 2 decimals? :)

Thanks again!

Also, do you allow me to release this as a modification? Others may need it too. Of course, I'll include the appropriate credits :)

glad we could solve it :)

2 decimals are very easy:

[sql]SELECT ROUND(AVG(YEAR(NOW()) - YEAR(birthday_search) - (DAYOFYEAR(birthday_search) - DAYOFYEAR(NOW())) / 365), 2) AS avgage
FROM testvb_user
WHERE YEAR(birthday_search)>0;[/sql]

feel free to release it