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Logikos
05-12-2005, 11:09 PM
In my code i'm using

$hack['dateline'] = vbdate($vboptions['dateformat'], $hack['dateline'], 1);


And calling the variable with $hack[dateline] and its showing up as 12-31-1969. Any ideas.

Paul M
05-12-2005, 11:16 PM
what value is in $hack['dateline'] before you call the function ?

Logikos
05-12-2005, 11:23 PM
The vaule of $hack[dateline] is whatever the value of TIMENOW is at the time it inserts into the database. This is weird i've never had a problem before.

WhSox21
05-13-2005, 12:00 AM
12-31-1969 means there is an invalid timestamp or something is wrong with the input where you call vbdate(). What's in the database? Check to make sure dateline is an integer and it has enough characters to hold a full timestamp. That's where I would start.

filburt1
05-16-2005, 04:23 AM
BTW, the significance of that date (or Jan 1 1970 as it sometimes will appear) is a timestamp or 0 or a negative value. A UNIX timestamp is the number of seconds since midnight of January 1st, 1970.