How do I...MySQL %LIKE% query

[eblivion]

How do I query the database using LIKE for an array but getting only results containing the full words instead of parts of it.

Here's a little chunk of what I have so far:

$keywords = explode(' ',$searchterm) ;

for ($i = 0; $i < sizeof($keywords); $i++){
$sql5b .= "description LIKE '%{$keywords[$i]}%'";
}

I have the query working, the problem is if one of the keywords is "class", the query will return results for: class, classic, midclass, classify, etc....

What I want to know is how to do the query where it will only return results for the word class and not other words containing it.

[JulianD]

How do I query the database using LIKE for an array but getting only results containing the full words instead of parts of it.

Here's a little chunk of what I have so far:

$keywords = explode(' ',$searchterm) ;

for ($i = 0; $i < sizeof($keywords); $i++){
$sql5b .= "description LIKE '%{$keywords[$i]}%'";
}

I have the query working, the problem is if one of the keywords is "class", the query will return results for: class, classic, midclass, classify, etc....

What I want to know is how to do the query where it will only return results for the word class and not other words containing it.
Hummm... Maybe adding white spaces around the keyword?

... WHERE description LIKE '% class %'

[eblivion]

Thanks. That's what I ended up doing....

The only drawback is if the word is at the beginning/end of the description and there's no white space before/after it.

Since this may occur in only a few searches, it's adequate for now.

~ Thanks again ~

[Andreas]

You might also want to use mySQL fulltext searching.