View Full Version : query question
burnist
04-10-2004, 06:13 PM
I want to select a row from a table thats contains a list of ids which is simple enough but i want to then take each id from that row (1 per coloum) and use it to select roms in another table. I cant think of anyway to do this as there would be new colums added to the first table quite frequently.
Dean C
04-10-2004, 06:35 PM
You can do queries within queries:
e.g. SELECT * FROM table WHERE(SELECT ids FROM table2);
I believe ^^
burnist
04-10-2004, 07:12 PM
$useritemsquery = $DB_site->query("SELECT id,name,icon FROM items WHERE id =('SELECT * FROM items_users WHERE userid=$bbuserinfo[userid]') ORDER BY id ASC");
while($useritems = $DB_site->fetch_array($useritemsquery)){
eval("\$showusersitem .= \"".fetch_template("itemshop_showuseritems")."\";");
}
Thats what i've go so far and i think what you ment works but i think it joins all the id's together into one big id and then the first query cant find the row and wont return it so the eval never happens
Christine
04-10-2004, 07:18 PM
You can do queries within queries:
e.g. SELECT * FROM table WHERE(SELECT ids FROM table2);
I believe ^^
Dean,
I think that isn't available until MySQL 5 (or is it 4.1)?
burnist
04-10-2004, 07:34 PM
^ crap i only run 4.0.18 :(
Dean C
04-11-2004, 01:26 PM
I'm pretty sure I read it in the mysql 4 manual :)
Christine
04-11-2004, 01:51 PM
Gotcha.
I had to dig it back up, because I didn't recall the specifics but it stuck out to me that 'I can't do this yet'.
Apparently, it isn't a matter of can't, it is a matter of how (and that is what changes in 4.1) For MySQL versions prior to 4.1, most subqueries can be successfully rewritten using joins and other methods.
http://dev.mysql.com/doc/mysql/en/Subqueries.html
http://dev.mysql.com/doc/mysql/en/Rewriting_subqueries.html
Glad I saw this thread!!
burnist
04-11-2004, 03:42 PM
So basicly im looking for something like this ??
$DB_site->query("SELECT id,name,icon FROM items
LEFT JOIN items_users ON items.id=items_users.*
WHERE items_users.userid IS $bbuserinfo[userid]; ORDER BY items.id ASC");
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