Getting forum ID through php?

[ButtKrust]

I was wondering how you go about getting the forum ID put into a variable or even just echo'd through PHP. Does it have anything to do with using the $_REQUEST['forumid']? Could someone give me a short code sample of how to echo a forum ID through PHP or point me to a topic that does? Just using "echo $_REQUEST['forumid']" doesn't work. I've tried searching but I can't find anything specific to what i need. thanks.

[Lynne]

It depends on where you are using the variable. Most people use it in a template and you can see all the places it is used in a template by doing a Search In Templates for "forumid" (no quotes). Note that the exact name of the variable is different depending on what template it is used in.

[ButtKrust]

I'm actually using it in a .php file which is displayed by a vbadvanced module. Would i need to connect to my database and pull the forum id from there instead? $foruminfo[forumid] isn't working.

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Actually when i put require_once('./global.php'); at the top of the page, i can get "echo $_REQUEST['forumid'];" to display '0', but not '5' which is the actualy forum id. Any ideas?

[Lynne]

Have you tried just $forumid? And, what are you getting the forumid *of*? That is the clue to actually getting it because you need to pull it from whatever query you are using. Unless you are actually in a forum, you won't have a forumid of anything unless you query for it.

[ButtKrust]

$forumid didn't work. I'm trying to get the forum ID of the forum that contains the module with this php file. I tried having it connect to the database and use "SELECT forumid FROM forum" but this output "Recource id #3" instead of '5', which again is the actual forum id that contains the module. I think i'm getting myself way off track...

[Mr-Moo]

Would you mind clarifying your entire objective a little more? After reading this Lynne has provided a solution, but I don't quite understand what you are looking for.

// Edit //
Is the forumID static or dynamic? What are the conditions?

[ButtKrust]

Alright I am using vbadvanced. I have a module of my forum which outputs a .php file. In this php file, i would like to find out the forum id in order that i might display something specific to each forum in that module. Just to keep things simple, though, i would like to echo or assign to a variable the forum ID that contains this module and php file. Basically when the page is loaded and the php file is loaded i want it to check the forum id so that i can set specific functions based on that forum id.

[Mr-Moo]

If I am not mistaken you are looking for something that does the following:

-When the forum page loads it checks the ForumID.
-If the forum ID matches a specific command, it outputs X item.

If this is what you are looking for, this is just a simple if else function.


<?php
if ($forumid = 1)
{
echo "Your desired output";
}
elseif ($forumid = 2)
{
echo "Desired output for 2";
}
else
{
echo "Desired output for FALSE";
}
?>

[ButtKrust]

$forumid decided to start working, i guess i missed it earlier. This is exactly what i needed, thank you both very much and i'm very sorry for misunderstanding so much.

[Mr-Moo]

No problem, was my code of any assistance, or were you simply in need of the $forumid portion?

[ButtKrust]

It was your code that made me realize that $forumid was in fact working in that php file ;-)

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I've actually got another problem now. When i use the part of your code like if(forumid=5) then do this, it works fine. AFTER this part of the code, then i can get "echo $forumid" to display something. However, If i simply try to use "echo $forumdisplay" WITHOUT any other code (such as the if statement), it doesn't display anything or work. Any reason why this happens? It seems that if($forumid = 5) is assigning the value of 5 to $forumid, rather than giving me the actual forumid. Since if i view this on a page where forum id is actually 6, it still displays 5 because that is what $forumid was assigned. I guess i'm back to my starting problem of pulling the actual forum id. I was fooled earlier.

[Lynne]

I don't understand the full problem (probably partly because I am totally unfamiliar with vbadvanced), but you are using php and thus the condition should be if($forumid == '1') - a double equal, not a single one.

[ButtKrust]

I'm just back at stage one it seems, i need to be able to recognize the current forum id with some sort of function. To keep it very simple, how would i output the current forum id with ECHO? In such a way that when i am at ForumA with the ID of 5, it will echo '5'. But when i go on over to forumB with ID of 6, it will echo '6'. This is what i'm really getting at.

[Mr-Moo]

Should be as simple as:


echo $forumid;


And thank you for that correction Lynne, you are correct. It was an operation being compared.

[ButtKrust]

Should be as simple as:


echo $forumid;


And thank you for that correction Lynne, you are correct. It was an operation being compared.

Is there a specific outside php file i need to "Include" at the top of my current php file in order for $forumid to actually work properly?

[Mr-Moo]

No, but then again I do not know where you are placing this at. What file are you editing? The global.php may need to be included.

[ButtKrust]

No, but then again I do not know where you are placing this at. What file are you editing? The global.php may need to be included.

in a separate php file all by itself. I guess that's my problem, i'll try including the global.

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Including global.php didn't work.. it must be that i have to include a file. I'll try to find the right one.

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If i include global.php and then use "Echo $foruminfo", it echoes "array" and if i use "Echo $foruminfo[forumid]" nothing comes out. I think i'm on to something by getting "array" to display, is there a way i can go about analyzing the array and extracting the forum id from it?

[Dismounted]

print_r($foruminfo);

[ButtKrust]

The only two things i've managed to have output anything while having global.php included are "Echo $foruminfo" which outputs the word "Array" and what you just posted, print_r($foruminfo) which outputs "Array ( )" So apparently it knows that $foruminfo is an array... how do i go about grabbing the forumid part of that array? No form of "$foruminfo['forumid']" seems to work. In fact when i use that, it outputs nothing rather than even the word array.

Keep in mind this is a separate php file so i know there's got to be some trick to grabbing the forum id from the separate php file, but i just can't figure out how. Am i missing some include files that need to be included?

[Dismounted]

Using the code I posted will allow you to see what is contained inside the array...