Version: 1.00, by Zzed
Developer Last Online: Feb 2012
Version: 2.2.x
Rating:
Released: 04-28-2002
Last Update: Never
Installs: 5
No support by the author.
This is a really simple hack that displays the number of users browsing the current forum along
with the list of users.
It requires no template changes.
In forumdisplay.php
find:
PHP Code:
if ($showforumusers) {
$datecut = $ourtimenow - $cookietimeout;
$browsers = '';
$comma = '';
$forumusers = $DB_site->query("SELECT username, invisible, userid
FROM user
WHERE inforum = $foruminfo[forumid] AND lastactivity > $datecut AND lastvisit <> lastactivity");
while ($forumuser = $DB_site->fetch_array($forumusers)) {
if ((!$forumuser['invisible'] or $bbuserinfo['usergroupid'] == 6) and $bbuserinfo['userid'] != $forumuser['userid']) {
$userid = $forumuser['userid'];
$username = $forumuser['username'];
if ($forumuser['invisible'] == 1) { // Invisible User but show to Admin
$invisibleuser = '*';
} else {
$invisibleuser = '';
}
eval("\$browsers .= \"".$comma.gettemplate('forumdisplay_loggedinuser')."\";");
$comma = ', ';
}
}
// Don't ask the DB for the user that is viewing the page as they wouldn't be here if they weren't! DOH!
// This way our query up above can hit the inforum index so don't change unless you know what you are doing.
if ((!$bbuserinfo['invisible'] or $bbuserinfo['usergroupid'] == 6) and $bbuserinfo['userid'] <> 0) {
$userid = $bbuserinfo['userid'];
$username = $bbuserinfo['username'];
if ($bbuserinfo['invisible'] == 1) { // Admin is invisible but show himself to himself, get it!
$invisibleuser = '*';
} else {
$invisibleuser = '';
}
eval("\$browsers .= \"".$comma.gettemplate('forumdisplay_loggedinuser')."\";");
}
if ($browsers) {
if (!$moderatedby) {
$onlineusers = "<br>";
}
eval("\$onlineusers .= \"".gettemplate('forumdisplay_loggedinusers')."\";");
}
}
And replace it with:
PHP Code:
if ($showforumusers) {
$datecut = $ourtimenow - $cookietimeout;
$browsers = '';
$comma = '';
$usercount = 0;
$forumusers = $DB_site->query("SELECT username, invisible, userid
FROM user
WHERE inforum = $foruminfo[forumid] AND lastactivity > $datecut AND lastvisit <> lastactivity");
while ($forumuser = $DB_site->fetch_array($forumusers)) {
if ((!$forumuser['invisible'] or $bbuserinfo['usergroupid'] == 6) and $bbuserinfo['userid'] != $forumuser['userid']) {
$userid = $forumuser['userid'];
$username = $forumuser['username'];
if ($forumuser['invisible'] == 1) { // Invisible User but show to Admin
$invisibleuser = '*';
} else {
$invisibleuser = '';
}
eval("\$browsers .= \"".$comma.gettemplate('forumdisplay_loggedinuser')."\";");
$comma = ', ';
$usercount++;
}
}
// Don't ask the DB for the user that is viewing the page as they wouldn't be here if they weren't! DOH!
// This way our query up above can hit the inforum index so don't change unless you know what you are doing.
if ((!$bbuserinfo['invisible'] or $bbuserinfo['usergroupid'] == 6) and $bbuserinfo['userid'] <> 0) {
$userid = $bbuserinfo['userid'];
$username = $bbuserinfo['username'];
if ($bbuserinfo['invisible'] == 1) { // Admin is invisible but show himself to himself, get it!
$invisibleuser = '*';
} else {
$invisibleuser = '';
}
$usercount++;
eval("\$browsers .= \"".$comma.gettemplate('forumdisplay_loggedinuser')."\";");
}
if ($browsers) {
$browsers = "<b>($usercount users)</b> $browsers";
if (!$moderatedby) {
$onlineusers = "<br>";
}
eval("\$onlineusers .= \"".gettemplate('forumdisplay_loggedinusers')."\";");
}
}
I am looking for the hack that vbulletin.org uses. It offers the number of users browsing the forum on the main index page. Anybody know how to do this?
I am trying to find the hack that vbulletin.org uses in the main forum index page. It displays the number of users browsing the forum in the forum name field??
Originally posted by Renegade I am trying to find the hack that vbulletin.org uses in the main forum index page. It displays the number of users browsing the forum in the forum name field??