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  #11  
Old 03-17-2002, 02:13 PM
N!ck N!ck is offline
 
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my problem now is that it only lists MY name!

the query:
Code:
SELECT COUNT(id) AS total, user.userid, user.username FROM user LEFT JOIN userphotos USING (userid) GROUP BY userphotos.userid ORDER BY user.usergroupid DESC, user.username LIMIT $offset, 15
($offset is set via a query string, or else it equals zero)

and also, i did COUNT(id) because id exists in the userphotos table and not in the user table.
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  #12  
Old 03-17-2002, 02:20 PM
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wooolF[RM] wooolF[RM] is offline
 
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]sry... can't help you...
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  #13  
Old 03-17-2002, 05:19 PM
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Freddie Bingham Freddie Bingham is offline
 
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try

GROUP BY user.userid instead of GROUP BY userphotos.userid

using COUNT(*) is faster than using COUNT(id)
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  #14  
Old 03-17-2002, 05:54 PM
N!ck N!ck is offline
 
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k thanks again
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  #15  
Old 03-17-2002, 05:56 PM
N!ck N!ck is offline
 
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okay, better...but now it outputs "1" instead of "0" (nobody has posted any pics yet, but they all have 1's next their names)
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  #16  
Old 03-17-2002, 08:37 PM
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Freddie Bingham Freddie Bingham is offline
 
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Try this
Code:
SELECT user.userid, user.username, count(userphotos.userid) AS total
FROM user
LEFT JOIN userphoto ON (userphoto.userid=user.userid)
GROUP BY user.userid
ORDER BY user.usergroupid DESC, user.username
LIMIT $offset, 15
This would give you then number of attachments each user has as I verified it. Since the above follows the same logic, it has to work.:
Code:
SELECT user.userid, user.username, count(attachment.userid) as attachmentcount
FROM user
LEFT JOIN attachment ON (user.userid=attachment.userid)
GROUP BY user.userid
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  #17  
Old 03-17-2002, 08:45 PM
N!ck N!ck is offline
 
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yes it appears to work just fine. thanks so much.
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