I can't figure out what I'm missing. I've attached a image to display the error I'm getting.
The first photo is the error I'm getting and the second photo is basically an illustration of where I would like the drop menu to start to list each forum of my site.
Thanks for your help in advance.
PHP Code:
<if condition="$show['popups']">
<!-- start vBMenu control element -->
<table class="tborder" cellpadding="4" cellspacing="1">
<tr>
<td id="ForumMENU" class="vbmenu_control">
<a href="#ForumMenu">Forum Menu</a>
<script type="text/javascript">
<!--
vbmenu_register("ForumMENU");
//-->
</script>
</td>
</tr>
</table>
<!-- end vBMenu control element -->
<!-- start vBMenu popup element -->
<div class="vbmenu_popup" id="ForumMENU_menu" style="display:none">
<table cellpadding="4" cellspacing="1" border="0">
<tr>
<td class="thead">Forums</td>
</tr>
<tr>
<td class="vbmenu_option"><a href="http://www.mysite.com/forums">Main Forum</a></td>
</tr>
<tr>
<td class="vbmenu_option"><a href="http://www.mysite.com/forums/forumdisplay.php?f=5">The FF Forums</a></td>
</tr>
<tr>
<td class="vbmenu_option"><a href="http://www.mysite.com/forums/forumdisplay.php?f=11">The FF Review Area</a></td>
</tr>
<tr>
<td class="vbmenu_option"><a href="http://www.mysite.com/forums/forumdisplay.php?f=16">Supported FF Sites</a></td>
</tr>
</table>
</div>
<!-- end vBMenu popup element -->
<else />
<!-- start alternative, non-vBMenu content -->
<table class="tborder" cellpadding="4" cellspacing="1">
<tr>
<td class="vbmenu_control"><a href="http://www.mysite.com/forums">Main Forum</a></td>
<td class="vbmenu_control"><a href="http://www.mysite.com/forums/forumdisplay.php?f=5">The Adult FF Forums</a></td>
<td class="vbmenu_control"><a href="http://www.mysite.com/forums/forumdisplay.php?f=11">The FF Review Area</a></td>
<td class="vbmenu_control"><a href="http://www.mysite.com/forums/forumdisplay.php?f=16">Supported FF Sites</a></td>
</tr>
</table>
<!-- end alternative content -->
</if>