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  #1  
Old 05-14-2006, 08:49 AM
Tim Skellett Tim Skellett is offline
 
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Default Coding question

Hi,
pardon this question (actually two); I'm a complete newbie when it comes to coding.

I would like to modify the following in a vB 3.5.4 template:

<if condition="$show['foo']">

and I would like to modify the above like so:

<if condition="$show['foo']" EXCEPT WHEN [if condition ="$A[X]" AND if condition"$[Y]"]>

or in other words do the operation as normal except when two other conditions are simultaneously met. How best do I code that?

Sorry if I sound painfully dumb; I am indeed a newbie.
______

That's the one question; my next question also refers to the above.
In the above, [Y] has a range of values, so I am looking at some kind of array, I suppose like so:

<if condition="$show['foo']" EXCEPT WHEN [if condition ="$A[X]" AND if condition"$[ARRAY(Y)]"]>

How best do I code that?

______

Many thanks in advance, and please pardon my ignorance.

It occurs to me it would be easier to do a nested "if" set, like so:

Code:
<if condition ="$A[X]" AND if condition"$[ARRAY(Y)]" AND if condition="$show"] show 'alternate'>
     else
             <if condition="$show['foo']" show 'foo'>
             </if>
</if>
Is my coding above correct?

Many thanks in advance for help and patience.
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  #2  
Old 05-14-2006, 05:01 PM
Adrian Schneider's Avatar
Adrian Schneider Adrian Schneider is offline
 
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Code:
<if condition="$show['foo'] and !$otherVarA and !$otherVarB">
You can seperate multiple conditions with and, or, xor, etc. ! means NOT, so the above condition is true when [ $show['foo'] is true, $otherVarA is false and $otherVarB is false ]
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  #3  
Old 05-14-2006, 07:40 PM
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Zachery Zachery is offline
 
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Don't use single quotes inside of template conditional varibles.

use $show[foo] instead of $show['foo']
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  #4  
Old 05-14-2006, 08:29 PM
Adrian Schneider's Avatar
Adrian Schneider Adrian Schneider is offline
 
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Quote:
Originally Posted by Zachery
Don't use single quotes inside of template conditional varibles.


use $show[foo] instead of $show['foo']
That is silly and somewhat incorrect:

If foo is a constant, you will run into some problems that will probably take hours to solve. Remember that conditions are parsed like so (NOT in double quotes!):

Code:
blah blah <if condition="$condition">Do this<else />Or Do This</if>blah blah
Code:
blah blah " . ($condition ? "Do This" : "Or Do This") . "blah blah
Example:
PHP Code:
<?php

define
('a''b');

$show['b'] = false;
$show['a'] = true;

echo (
$show[a]) ? 'Working as expected' 'Uh Oh!';

// outputs 'Uh Oh!'
?>
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  #5  
Old 05-15-2006, 05:15 AM
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Zachery Zachery is offline
 
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Default

Quote:
Originally Posted by SirAdrian
That is silly and somewhat incorrect:

If foo is a constant, you will run into some problems that will probably take hours to solve. Remember that conditions are parsed like so (NOT in double quotes!):

Code:
blah blah <if condition="$condition">Do this<else />Or Do This</if>blah blah
Code:
blah blah " . ($condition ? "Do This" : "Or Do This") . "blah blah
Example:
PHP Code:
<?php

define
('a''b');

$show['b'] = false;
$show['a'] = true;

echo (
$show[a]) ? 'Working as expected' 'Uh Oh!';

// outputs 'Uh Oh!'
?>
I've always run into problems using single quotes inside of the varibles, and it goes away generally when I remove them.
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  #6  
Old 05-15-2006, 05:18 AM
Adrian Schneider's Avatar
Adrian Schneider Adrian Schneider is offline
 
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Quote:
Originally Posted by Zachery
I've always run into problems using single quotes inside of the varibles, and it goes away generally when I remove them.
Inside templates you can't use single quotes unless you wrap the variable in braces... In *conditions* though it is not parsed within double quotes. Hope that clears it up.
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