Average Age

[pgowder]

I'd like to compute the average age of my users for statistical information.

Any ideas on how to write this query?

[Admin]

The query:

SELECT YEAR(NOW())-AVG(YEAR(birthday)) AS avgage FROM user;

You might want to round() it later, or you can do it directly in the query using MySQL's ROUND() function, for example:

SELECT [high]ROUND([/high]YEAR(NOW())-AVG(YEAR(birthday))[high],2)[/high] AS avgage FROM user;

will round it to 2 decimal points.

[pgowder]

How can I eliminate the ones that didn't input a year?

[Psychdrone]

wow sweet!

Where would I put this code and where would I recieve the results!

[FWC]

[QUOTE]Originally posted by pgowder
How can I eliminate the ones that didn't input a year?

[pgowder]

Here is what I tried:

[QUOTE]SELECT YEAR(NOW())-AVG(YEAR(birthday)) AS avgage
WHERE birthday != 0000-00-00 FROM user

[FWC]

After FROM user:

SELECT YEAR(NOW())-AVG(YEAR(birthday)) AS avgage FROM user WHERE birthday != 0000-00-00

That doesn't error, but I got a strange result. My average user is 216 years old.

I think it may be because we are excluding the the unset year cells but the total rows aren't changing when the average is calculated.

[Psychdrone]

could someone answer me please!

Thanks!

[Freddie Bingham]

SELECT YEAR(NOW())-AVG(YEAR(birthday)) AS avgage FROM user WHERE YEAR(birthday) <> 0

I wasn't aware of the YEAR() function, I will have to check that out.

[FWC]

[QUOTE]Originally posted by freddie

SELECT YEAR(NOW())-AVG(YEAR(birthday)) AS avgage FROM user WHERE YEAR(birthday) <> 0

I wasn't aware of the YEAR() function, I will have to check that out.