getting a $name evaluated

[jjj0923]

I'm somewhat confused.

I've developed some additional code in index.php

PHP Code:

$fbmenu='';
if ($lastphoto < $userlastvisit) { 
    eval("\$fbmenu = \"".gettemplate('fb_menu')."\";"); 
} else {  
    eval("\$fbmenu = \"".gettemplate('fb_menu1')."\";"); 
} 


I've added fb_menu and fb_menu1 to my templates and added $fbmenu to the code in the 'Header' template but it won't evaluate and display the html contained in the fb_menu or fb_menu1 template.
My php code is down near the bottom of index.php and it outside of any conditional clauses and I know it's working fine because I did lots of testing before implementing it.

Does Vbulletin NOT evaluate code in templates (such as header)?
I've done this before but and added $variables associated with templates in index.php but the results of that code ($'name') was placed in forum_home

this one really has me stumped.... I know my php code is working, but vb doesn't want to associate $fbmenu with my template... any ideas???

thanks in advance.

- jeff

[Admin]

You need to place that code in global.php before $header is eval()'ed.

[jjj0923]

firefly, I'm almost there, byt placing the code right before loading the header template breaks the following:

1) logged out users cannot log-in
2) new users that have just registered cannot log in.

other than that; the code (for registered users) who have not logged out works great.

here's my code; do you have any ideas?

PHP Code:

// begin hack for testing when last photo was posted compared to last date user visited site

$fbmenu='';
eval("\$fbmenu = \"".gettemplate('fb_menu')."\";");

echo $userlastvisit;

$user=$DB_site->query_first("SELECT * FROM user WHERE userid=$bbuserinfo[userid]");
$username=$user[username];
$userlastvisit=$user['lastvisit'];

$db1name = "PhotoPost_info";          
$link_id = mysql_connect($servername, $dbusername, $dbpassword);
mysql_select_db($db1name, $link_id);
$result = mysql_query("SELECT max(photos.date) as lastphoto from photos");
while($query_data = mysql_fetch_row($result)) { $lastphoto = $query_data[0]; }
mysql_select_db($dbname);

if ($lastphoto < $userlastvisit) {
        eval("\$fbmenu = \"".gettemplate('fb_menu')."\";");
    } else {
        eval("\$fbmenu = \"".gettemplate('fb_menu1')."\";");
    }

// end hack 


[Admin]

You use $username in your code which breaks the log-in form. Just use $bbuserinfo[username] and $bbuserinfo[lastvisit], you don't need another query for that. And you also don't need to create another database connection, just use the current opened one.

[jjj0923]

oh yea...
much nicer...
I also changed the perl code in Photo Post to simply write a 10 character text file with the most recent post date and used an fopen in global.php to read it....

much nicer, much faster and working great!

thank!

- jeff

[Admin]

No problems.