The Arcive of Official vBulletin Modifications Site.It is not a VB3 engine, just a parsed copy! |
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if ($vbulletin->options['fireworks_enabled'] && $vbulletin->userinfo['$vbulletin->options[\'fireworks_field\']'])
How can I make that so my if my field = yes it displays the code and if it = no it doesn't. Would this be correct? if ($vbulletin->options['fireworks_enabled'] && $vbulletin->userinfo['$vbulletin->options[\'fireworks_field\']'] = Yes) BTW $vbulletin->options[\'fireworks_field\'] is linked to my vbulletin profile field which is 142. |
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X vBulletin 3.8.12 by vBS Debug Information | |
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