[harmor19]

I am getting a sql error

Here's the php

PHP Code:

$vbulletin->input->clean_array_gpc('p', array(
    'name' => TYPE_STR,
    'email' => TYPE_STR,
    'text' => TYPE_STR,
    'testid' => TYPE_INT
     ));

     $db->query_write("
    UPDATE " . TABLE_PREFIX . "testimonials SET
    name = '" . $db->escape_string($vbulletin->GPC['name']) . "',
    email = '" . $db->escape_string($vbulletin->GPC['email']) . "',
    text = '" . $db->escape_string($vbulletin->GPC['text']) . "',
    WHERE testid = " . $vbulletin->GPC['testid'] . "
    "); 


Here's the sql error

UPDATE testimonials SET
    name = 'erg4ewg',
    email = 'ewgwgew',
    text = 'gewgewrg <b>egeg</b>',
    WHERE testid = 1;

MySQL Error  : You have an error in your SQL syntax.  Check the manual that corresponds to your MySQL server version for the right syntax to use near 'WHERE testid = 1' at line 5
Error Number : 1064