[filburt1]

I have a table called (for example) "votes" with the following structure:

"userid:" INT(10) UNSIGNED NOT NULL DEFAULT 0
"entryid:" INT(10) UNSIGNED NOT NULL DEFAULT 0

...with a unique grouping on those two columns.

It is related to another table I have called "entries" with the following general structure:

"entryid:" same as "votes"'s entryid column (the two tables relate to each other through this column)
"year": YEAR DEFAULT 1970
"month": INT(2) UNSIGNED DEFAULT 1
column4
column5
.
.
.

...plus some additional columns in "entries."

For each unique year/month combination, how can I find out which entry got the most number of votes?

For example, I believe this query gets the entryid and the associated entry data that has the most votes in the "votes" table for February 2005:
[sql]
SELECT v.entryid, COUNT(v.userid) AS votecount, e.column4, e.column5... FROM votes v, entries e WHERE v.entryid = e.entryid AND e.month = 2 AND e.year = 2005 ORDER BY votecount DESC LIMIT 1
[/sql]
Without querying in a loop, how can I extend the query so that it gets the winning entry for each month and year (i.e., the winner for February 2005, March 2005, etc.) instead of just one given month? I do not know how to do this given MySQL does not let you give ORDER BY power over GROUP BY.