Another question:
in
PHP Code:
$keeparray = $DB_site->query("SELECT 'name','catchname','data' FROM tacemonquery WHERE name='$th_old_name'");
I'd reference "name", "catchname" and "data" by
$keeparray['name'] or $keeparray[name], right? Because it's not working, Maybe something's wrong with the query....
Help?
also, this:
PHP Code:
$DB_site->query("ALTER TABLE user CHANGE '$keeparray[catchname]', '$th_rong_name'");
Returns an error, PRESUMABLY because the two variables, both of which are set based on the keeparray mentioned above, are assigned no value... That aside, is the syntax right to change user field $keeparray[catchname] to $th_rong_name ?