[ManagerJosh]

Originally posted by MUG
You can't use quotes when dealing with arrays in double-quotes. Try:

PHP Code:

if (substr($target, -1) != '/') $target .= "/$manufacturers_data[manufacturers_directory]"; 


Wouldn't that affect my variable in the first place? Because my variable is:

PHP Code:


$manufacturers_data['manufacturers_directory'] 


where i have specified earlier that:

PHP Code:

    $manufacturers_array = array(array('id' => '', 'text' => TEXT_NONE));
    $manufacturers_query = tep_db_query("select manufacturers_id, manufacturers_name, manufacturers_directory from " . TABLE_MANUFACTURERS . " order by manufacturers_name");
    while ($manufacturers = tep_db_fetch_array($manufacturers_query)) {
      $manufacturers_array[] = array('id' => $manufacturers['manufacturers_id'],
                                     'text' => $manufacturers['manufacturers_name']);
    }
    
// Directory Code Hack
    $manufacturers_data = tep_db_fetch_array($manufacturers_query);
// Directory Code Hack 


Edited: your suggestion works MUG, but I wonder if it affects my variable...