Quote:
Originally posted by wooolF[RM]
everything from my script works except 3 thing:
PHP Code:
{echo mysql_result($totalonline,0);} echo("<br><br>");
{echo mysql_result($numbervisible,0);} echo("<br><br>");
{echo mysql_result($numberguest,0);} echo("<br><br>");
This means I get parse errors when I wan to see how many members are online in total/members/guests...
$totalonline=$numberregistered+$numberguest;
$numberinvisible=$numberregistered-$numbervisible;
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$totalonline and $numberinvisible variables are not query result resources, they are ordinary integer variables so why do you use them inside mysql_result?
As for "$loggedins": use that one in mysql_result because it is a query result. So you should use it like that:
$numberguest=mysql_result($loggedins,0);