insert:
echo "warnfield=$warnfield <br>";
echo "bbuserinfo=$bbuserinfo<br>";
before
$warnlevel = $DB_site->query_first("SELECT $warnfield FROM userfield WHERE userid='$bbuserinfo'");
and see what your variables have before entering the query.
BTW isnt it the variable "$bbuserinfo[userid]" you should use in your query if I got what you're trying to do right?
if yes try this:
$new_var_323= $bbuserinfo[userid];
$warnlevel = $DB_site->query_first("SELECT $warnfield FROM userfield WHERE userid='$new_var_323'");
Hope this helps..
Regards,
Logician
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