[Jawelin]

Hi. I found probably a bug in the replacement variable feature of VB 2.2.1 (and below, I guess).
You can find more information here in vb.org ...

Well, with a little studying, I found out the actual replacement code is in functions.php, here:

PHP Code:

  while ($var=$DB_site->fetch_array($vars)) {
    if ($var['findword']!="") {
      $newtext=str_replace($var['findword'],$var['replaceword'],$newtext);
    }
  } 


My question is: your own opinion, could I generate any side effect replaceing the above line with the following one ?

PHP Code:

      $newtext=str_replace(strtoupper($var['findword']),$var['replaceword'],strtoupper($newtext)); 


I.e., this way, the $newtext variable is assigned from the strtoupper($newtext) or - hopefully - all the findword occurrences are replaced into the original $newtext, which remains the same ?



Thank you for any help.
Bye