Quote:
Originally Posted by MoT3rror
Try
Code:
<if condition="THIS_SCRIPT = 'forumdisplay' AND $forumid == 32">
<image scr="images/Mustanglogo.jpg" />
<else />
<image src="linktosecondimage" />
</if>
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Thanks for the reply... after using the entry I am getting the folowing error
The following error occurred when attempting to evaluate this template:
Parse error: parse error, unexpected '=' in /vb/includes/adminfunctions_template.php(3716) : eval()'d code on line 15