[steadicamop]

I have asked a friend of mine, who's pretty clued up with php and he gave me this code:

PHP Code:

$ref = str_replace(array('http://','www.'),array('',''),$vboptions['bburl']); 


And as I've read it, str_replace works by searching the first part (array('http://','www.')) then replaces it with the next (array('','')) and looking in the last part for the source ($vboptions['bburl']) - but this isn't working, just giving an error:

Warning: strstr() [function.strstr]: Empty delimiter. in /attachment.php(112) : eval()'d code on line 3

Which is this line:

PHP Code:

if(!strstr($_SERVER['HTTP_REFERER'],$ref)) { 


Now I'm in teritory I don't fully understand - but there is something to do with the strstr function that has caused the error.

Beyond that I'm lost .... can anyone shed any light on this?

Cheers

Jason