*sigh* nope, bascially what I want to do is similar to the html "post" method in forms, but it has to be in php because I am executing it via shell and have no access to html. File b.php is on someone elses server and i have no access to it so no includes. The closest thing that I can think of that might do this is spam bots that file out forms and such.
I have $POST1 and I want to "pass" it to b.php How would I do that inside a script?
EDIT: it would be the opposite of include() or require()
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