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Revan

09-07-2004 05:13 AM

php integer

How can I check if an integer is an even number?
I want to have a submit button and for each of the users that clicks it, it adds their usernames to a field in a table.
However, I cannot have the # of users to be an uneven number (IE 1, 3, 5, 7 etc).
So there is my problem.

Anyone?

Tekton

09-07-2004 07:08 AM

I'm sure there are prolly cleaner ways to write this, but....

Code:

if($value % 2 == 0) 

  { 

    // it's even

  }else{ 

    $value += 1;  // or whatever 

  }

Colin F

09-07-2004 07:40 AM

you could do something like this... if you don't find a better way :)

if (($number/2) == (intval(($number+1)/2))
{
//is even number
}
else
{
//is uneven number
}

Revan

09-07-2004 02:33 PM

Cheers people :)
I tried both of them first with a single figured number, and they both worked fine.
I then tried with 20000000000000000000 just for the hell of it. Colins code said this was uneven, while Tektons said even.
Then I tried with 20000000000000000001 which reversedly Colins code called uneven, while Tektons called it even.
:p

Now I dont need such a high number, just 100 or so. And they both say thats even XD
Thanks again guys :)

filburt1

09-07-2004 02:55 PM

Quote:

Originally Posted by Revan

Tekton's method is by far more preferable (modulus division).

PHP Code:


		
			
if ($number % 2 == 0)

...evaulates to true if the number is evenly divisible by 2 (i.e., even).

Dean C

09-07-2004 03:37 PM

Also it's always nice to write a function for these things :)

PHP Code:


		
			
function is_even($num)

{

        if($number % 2 == 0)

        {

                return true;

        }

        else

        {

                return false;

        }

}

Then to check if it's even use this:

PHP Code:


		
			
$number = 2;

if(is_even($number))

{

       echo 'it\'s even!';

}

else

{

        echo 'it\'s not even!';

}

Revan

09-07-2004 05:35 PM

Added the fucntion for future usage :)
But I feel pretty sure that the arguement in the function ($num in above) and the function coding ($number in above) should be equal ;) hehe

Dean C

09-07-2004 05:45 PM

Yep you're write, I've been programming all day so that's my excuse ;)

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