grabbing results even though some WHERE's are false
 

ok basically im writing a searching script but when i dont type in an image name, an artist name,but i type in a gallery id it says there are none cause its selecting with image name and artist name being nothing. is there a away around this so it will just select everything with that gallery id even though image name and artist name are set to nothing?

Or :)

but i still want to if like artist name has some value that it will also refine the results from gallery id and remove those results which arent equal to artist name

OK, so let's figure out what you want ;)

If I am right we're talking about 3 fields: Image Name, Artist Name and Gallery ID.

Pleasse tell me what you want to have returned in each of the following cases:

• Only Gallery ID given
• Only Artist Name given
• Only Image Name given
• Artist Name and Image Name given
• Artist Name and Gallery ID given
• Image Name and Gallery ID given
• Artist Name, Image Name and Gallry ID given

in all those cases i want all the data in my gallery table to be returned which matches the criteria in WHERE

Yeah ;)
And what IS the criteria?

Can you post the query or the code for us to see? Would help solve the problem.

This will return all rows from table gallery wher gallery_id is $gallery, artist_name ist $artitstname and image_name is $imgname.

But it seems like this is not what you want.

I've asked before how you want your conditions, but you did not gave me a useful answer so I can only guess:

[sql]
SELECT * FROM gallery WHERE (gallery_id = '$gallery' AND '$artistname'='' AND '$imgname'='') OR (gallery_id='$gallery' AND artist_name='$artistname' AND image_name='$imgname')
[/sql]

This will return all rows table gallery wher gallery ID is $gallery, artist_name ist $artitstname and image_name is $imgname, or all rows from table gallery where gallery ID is $gallery and $artistname, $imgname are empty.

A better way would be to construct your query in PHP so it does only contain conditions for columns you really care for.

ok i see how it will work;)
did you see mess up on the first one? '$imgname'='' ?