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-   vB3 General Discussions (https://vborg.vbsupport.ru/forumdisplay.php?f=111)
-   -   Need help finishing... (https://vborg.vbsupport.ru/showthread.php?t=54371)

Chris M 06-15-2003 02:35 PM
Need help finishing...
 
The score grabbing works, but now I need the the values in the "gscore,sscore,hscore and rscore" fields;)

So far, they return:

gscore
sscore
hscore
rscore

I am not sure what type of field they should be (I have them set as INT:confused:), and they are a point value, with gscore being 4 and sscore being 1...

This code is what needs to be modified to get the value (everything else works:D):)

Code:
          $score = $DB_site->query_first("SELECT '$whichscore' FROM *tablename*_questions WHERE qid='$theqid'");

if ($bbuserinfo['usergroupid']==2)
{
$DB_site->query("UPDATE user SET question1='$theqid',score1='$score[$whichscore]' WHERE userid='$bbuserinfo[userid]'");
}
Any help?:)

Satan

Chris M 06-16-2003 06:14 AM
Please can anyone help?

I really need to get this finished...

Satan

Cloudrunner 06-16-2003 06:40 AM
Quote:
Code:
          $score = $DB_site->query_first("SELECT '$whichscore' FROM *tablename*_questions WHERE qid='$theqid'");

if ($bbuserinfo['usergroupid']==2)
{
$DB_site->query("UPDATE user SET question1='$theqid',score1='$score[$whichscore]' WHERE userid='$bbuserinfo[userid]'");
}
Any help?:)

Satan
Try changing the code thusly:

PHP Code:
$score = $DB_site->query_first("SELECT whichscore FROM *tablename*_questions WHERE qid = '"
                               .$theqid
                               ."'");

if ($bbuserinfo['usergroupid'] == 2){
  $DB_site->query("UPDATE user SET question1 = '"
                  .$theqid
                  ."', score1 = '"
                  .$score[whichscore]
                  ."' WHERE userid = '"
                  .$bbuserinfo[userid]
                  ."'");
} 
Of course I am assuming that $whichscore is a column name and not a variable that has been pre-defined previously in the code. If my assumption is correct then removing the "$" effectively turns whichscore into an array identifier.

If on the other-hand, $whichscore IS a variable, then I would do the code like this:

PHP Code:
$score = $DB_site->query_first("SELECT '"
                               .$whichscore
                               ."' FROM *tablename*_questions WHERE qid = '"
                               .$theqid
                               ."'");

if ($bbuserinfo['usergroupid'] == 2){
  $DB_site->query("UPDATE user SET question1 = '"
                  .$theqid
                  ."', score1 = '"
                  .$score[$whichscore]
                  ."' WHERE userid = '"
                  .$bbuserinfo[userid]."'");
} 
Lemme know if this helps or if I'm just blowing smoke up my own arse. I could probably figure it out with you if I had abit more reference code to go by... ;)

p.s. I always break out of quotes when calling variables, just for my own piece of mind. I know you don't have to, but I do unless I'm required to not do it.

Chris M 06-16-2003 07:04 AM
Aha thanks...

Yes $whichscore is a earlier defined variable, via this code:

Code:
if ($answer==$ganswer) {
 $whichscore = 'gscore';
}elseif ($answer==$sanswer) {
 $whichscore = 'sscore';
}elseif ($answer==$hanswer) {
 $whichscore = 'hscore';
}else{
 $whichscore = 'rscore';
}
I will try your code, but if it doesn't work, all I can suggest is that the $answer variable is not being intval'ed properly;)

Thanks - I'll try this:)

Satan

Chris M 06-16-2003 07:28 AM
:(

Unfortunately the code still returns "gscore" , "hscore", "sscore" and "rscore":(

Satan

Cloudrunner 06-16-2003 07:29 AM
Quote:
Code:
if ($answer==$ganswer) {
 $whichscore = 'gscore';
}elseif ($answer==$sanswer) {
 $whichscore = 'sscore';
}elseif ($answer==$hanswer) {
 $whichscore = 'hscore';
}else{
 $whichscore = 'rscore';
}

I may be seeing things strangely, but if g, s, h, and rscore are all variables, shouldn't they be prefixed with "$"?

Like this?

PHP Code:
if ($answer == $ganswer){
  $whichscore = $gscore;
} elseif ($answer == $sanswer){
  $whichscore = $sscore;
} elseif ($answer == $hanswer){
  $whichscore = $hscore;
} else {
  $whichscore = $rscore;
} 
If the *score fields contain any thing I'm thinking that they should be called as variables, so that when you make $whichscore equivalent to them, then $whichscore would be == the information that they contain. As it sits now with what you provided, then $whichscore is equivalent not to the information that the *score fields contain, but to their string names only.

So assuming that:
PHP Code:
$gscore = 1;
$sscore = 2;
$hscore = 3;
$rscore = 4; 
Then with your code, $whichscore would output the name (whichever meets the if statement criteria). Using the one I suggest, the if $answer doesn't equal any of the *answer comparators, then $whichscore will contain and output "4".

Chris M 06-16-2003 07:34 AM
Hmm...I never thought of that - I shall try, thanks:D:)

Satan

Cloudrunner 06-16-2003 07:40 AM
np...lemme know.

Chris M 06-16-2003 07:53 AM
Ok...That didnt work...

But then I had an idea - Why query the database for "$whichscore" if the score value is already defined - So I was thinking:

Code:
if ($answer == $ganswer){
$score = $gscore;
} elseif ($answer == $sanswer){
$score = $sscore;
} elseif ($answer == $hanswer){
$score = $hscore;
} else {
$score = $rscore;
}

$gscore = 4;
$hscore = 3;
$rscore = 2;
$sscore = 1;

if ($bbuserinfo['usergroupid'] == 2){
  $DB_site->query("UPDATE user SET question1 = '"
                  .$theqid
                  ."', score1 = '"
                  .$score ."'
                  WHERE userid = '"
                  .$bbuserinfo[userid]."'");
}
Think I should try it?:)

Edit: It didn't work:(

Satan

Chris M 06-16-2003 07:59 AM
Ah...

If the answer is a numerical value, $answer returns the numerical value of that answer (i.e. if the first answer was 93, $answer returns 93)

If the answer is a non-numerical value, $answer returns 0:(

Satan


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