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-   -   checkbox (https://vborg.vbsupport.ru/showthread.php?t=46457)

hidjra 12-07-2002 12:41 PM

checkbox
 
hi guys,

can anyone help me with this, it has nothing to do with vbulletin.

i want to write/pull some info to/from the database, and show the values in checkboxes, for example;

when a user signs up, he/she checks his interests in a form with checkboxes, this form puts the values into a database table, seperated with a space. And afterwards the user should have the possibility to change this info.

How do i make a form that puts multiple values in one table, seperated with a space?
And afterwards; how do i make a form that pulls the info from the database, en checks the checkbox if values are found in the table?

does this make any sense?? :cross-eyed:

Hidjra

hidjra 12-07-2002 12:46 PM

i tried this, but this only works when a user checks just one of the checkboxes :knockedout:


PHP Code:


$haalartiest 
mysql_query("select artiestid,naam,synoniem,land,genre from club_artiest WHERE artiestid ='$artiestid'");
$array $DB_site->fetch_array($haalartiest);


if (
$array[genre] == "0") {
    
$genre0 "checked";
  } elseif (
$array[genre] == "1") {
    
$genre1 "checked";
  } elseif (
$array[genre] == "2") {
    
$genre2 "checked";
  } elseif (
$array[genre] == "3") {
    
$genre3 "checked";
  } elseif (
$array[genre] == "4") {
    
$genre4 "checked";
  } elseif (
$array[genre] == "5") {
    
$genre5 "checked";
  } elseif (
$array[genre] == "6") {
    
$genre6 "checked";
  } elseif (
$array[genre] == "7") {
    
$genre7 "checked";
  } elseif (
$array[genre] == "8") {
    
$genre8 "checked";
  } 



PHP Code:

<input type=\"checkbox\" name=\"genre\" value=\"1\" $genre1>
<input type=\"checkbox\" name=\"genre\" value=\"2\" 
$genre2>
<input type=\"checkbox\" name=\"genre\" value=\"3\" 
$genre3>
<input type=\"checkbox\" name=\"genre\" value=\"4\" 
$genre4>
<input type=\"checkbox\" name=\"genre\" value=\"5\" 
$genre5>
<input type=\"checkbox\" name=\"genre\" value=\"6\" 
$genre6>
<input type=\"checkbox\" name=\"genre\" value=\"7\" 
$genre7>
<input type=\"checkbox\" name=\"genre\" value=\"8\" 
$genre8

so what's wrong with this picture

hidjra

Sparkz 12-07-2002 01:36 PM

The checkboxes need to have unique names, for starters...

hidjra 12-10-2002 09:10 AM

ok, i gave the checkboxes a unique name, and i succeeded in writing the value to the table, seperated with a space

PHP Code:

<input type="checkbox\" name=\"genre[]\" value=\"1\" $genre1>
<input type=\"checkbox\" name=\"genre[]\" value=\"2\" 
$genre2>
<input type=\"checkbox\" name=\"genre[]\" value=\"3\" 
$genre3>
<input type=\"checkbox\" name=\"genre[]\" value=\"4\" 
$genre4>
<input type=\"checkbox\" name=\"genre[]\" value=\"5\" 
$genre5>
<input type=\"checkbox\" name=\"genre[]\" value=\"6\" 
$genre6>
<input type=\"checkbox\" name=\"genre[]\" value=\"7\" 
$genre7>
<input type=\"checkbox\" name=\"genre[]\" value=\"8\" 
$genre8

PHP Code:

$genres implode($genre" ");
    
mysql_query("insert into club_artiest (naam, synoniem, land, genre) values ('$naam', '$synoniem', '$land' , '$genres')"); 

but what do i have to change in here to display the checkboxes as checked when editing an entry ?

PHP Code:

if ($array[genre] == "0") {
    
$genre0 "checked";
  } elseif (
$array[genre] == "1") {
    
$genre1 "checked";
  } elseif (
$array[genre] == "2") {
    
$genre2 "checked";
  } elseif (
$array[genre] == "3") {
    
$genre3 "checked";
  } elseif (
$array[genre] == "4") {
    
$genre4 "checked";
  } elseif (
$array[genre] == "5") {
    
$genre5 "checked";
  } elseif (
$array[genre] == "6") {
    
$genre6 "checked";
  } elseif (
$array[genre] == "7") {
    
$genre7 "checked";
  } elseif (
$array[genre] == "8") {
    
$genre8 "checked";
  } 


hidjra 12-11-2002 08:19 AM

nobody?? hello guys :speechless: help needed :D

Hidjra


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