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Dragomancer

05-20-2002 09:17 PM

Variable in a Variable ?

Hi,
I'm currently working with a html-form, and I've got a lot of variables to work through. Because the form is generated dynamicly, I don't know how many variables I'll get. My code is looking like this:

PHP Code:


		
			
if($test1==1){

 ...}

if($test2==1){

 ...}

if($test3==1){

 ...}

if($test4==1){

 ...}

if($test5==1){

 ...}

Could someone please help by tell me how to combine '$test' into a "double" variable, so it would somehow look like this:

PHP Code:


		
			
$count=1;

while(isset($test$count)){

 if ($test$count==1){

  ....

 }

 $count++;

}

Thanks for your help.

Superbronx

05-20-2002 09:32 PM

If your talking about arrays, this is what you would do -

$test[$count]

If your talking about combining the string, this is what you would do -

$another_variable = ($test).($count)

Hope that helped.

Mark Hensler

05-20-2002 09:46 PM

PHP Code:


		
			
$count=1;

while(isset(${"test".$count})){

 if (${"test".$count}==1){

  ....

 }

 $count++;

}

Admin

05-21-2002 08:57 AM

Read all about variable variables here:
http://www.php.net/manual/en/languag...s.variable.php

Dragomancer

05-21-2002 12:06 PM

Quote:

Originally posted by Mark Hensler

PHP Code:

$count=1; while(isset(${"test".$count})){ if (${"test".$count}==1){ .... } $count++; }

Thanxs, that's what i was looking for.

Admin

05-21-2002 12:27 PM

Since it's a POSTed form, you can also use the $_POST array ($HTTP_POST_VARS for older PHP versions).

PHP Code:


		
			
foreach ($_POST as $variable => $value) {

    // $variable would be 'test1', 'test2', 'test3', 'test4' etc.

    // And $value would be whatever the user entered in the form

}

Use print_r() to see exactly what the $_POST array contains, and see how it can be useful:

PHP Code:


		
			
print_r($_POST);

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