vb.org Archive - a bit of code in need of fixing

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- Member Archives (https://vborg.vbsupport.ru/forumdisplay.php?f=202)

- - a bit of code in need of fixing (https://vborg.vbsupport.ru/showthread.php?t=36882)

E	04-02-2002 04:19 AM

a bit of code in need of fixing

part of a hack im making:

PHP Code:


		
			
 //Drakks Warning Hack

$warnifield="field10" //make x the field for ur warning level

$warnlevel = $DB_site->query_first("SELECT $warnifield FROM userfield WHERE $userid=$bbuserinfo");

        if ($warnlevel >= "10") {

                $warnphraze="NEEDS BANNING";    //u may set the warn phraze for each one

        } elseif ($warnlevel >= "7") {

                $warnphraze="Very Bad";

        } elseif ($warnlevel >= "4") {

                $warnphraze="Thats Rough";

        } elseif ($warnlevel >= "1") {

                $warnphraze="Evil's Apprentice";

        } else {

                $warnphraze= "Goody Goody";

        }

        if ($warnfield >= "10") {

                $warning='<img src="{imagefolder}/warn1.jpg"> $warnphraze';

        } elseif ($warnlevel >= "7") {

                $warning='<img src="{imagefolder}/warn2.jpg"> $warnphraze';

        } elseif ($warnlevel >= "4") {

                $warning='<img src="{imagefolder}/warn3.gif"> $warnphraze';

        } elseif ($warnlevel >= "1") {

                $warning='<img src="{imagefolder}/warn4.gif"> $warnphraze';

        } else {

                $warning='<img src="{imagefolder}/warn5.gif"> $warnphraze';

        }

//End Warning hack

Theres also an error with the query,,, but... how can i get $warning too =<img src="{imagefolder}/warn5.gif"> and so on?

i know that Wont work.. how can i change it too make it work

TECK	04-02-2002 05:22 AM

did you tried:

PHP Code:


		
			
$warning='<img src="{imagefolder}/warn1.jpg"> $warnphraze'

E	04-02-2002 05:25 AM

hmm...

E	04-02-2002 05:41 AM

theres still the error with this line :

PHP Code:


		
			
$warnlevel = $DB_site->query_first("SELECT $warnfield FROM userfield WHERE userid='$bbuserinfo'");

i also tried changing it too:

PHP Code:


		
			
$warnlevel = $DB_site->query_first("SELECT $warnfield FROM userfield WHERE userid=$userid");

Logician

04-02-2002 07:26 AM

insert:
echo "warnfield=$warnfield <br>";
echo "bbuserinfo=$bbuserinfo<br>";
before
$warnlevel = $DB_site->query_first("SELECT $warnfield FROM userfield WHERE userid='$bbuserinfo'");

and see what your variables have before entering the query.

BTW isnt it the variable "$bbuserinfo[userid]" you should use in your query if I got what you're trying to do right?

if yes try this:
$new_var_323= $bbuserinfo[userid];
$warnlevel = $DB_site->query_first("SELECT $warnfield FROM userfield WHERE userid='$new_var_323'");

Hope this helps..

Regards,
Logician

E	04-02-2002 07:33 AM

it seems no matter what i do i get this error:

Parse error: parse error in /home/fiendwor/public_html/admin/functions.php on line 214

Fatal error: Call to undefined function: getuserinfo() in /home/fiendwor/public_html/admin/sessions.php on line 323

E	04-02-2002 07:36 AM

it doesnt like this code:
echo "warnfield=$warnfield <br>";

if thats not there it doesnt like this code:
$new_var_323= $bbuserinfo[userid];

if thats not there it doesnt like the query

Logician

04-02-2002 07:48 AM

what editor program do you use? Cant you see which line produced the error? I strongly suggest you using an editor that can show you line numbers and then you can easily point which line is causing you trouble. It would be a real headache to trace and fix the problem without even knowing which line causes the problem!

E	04-02-2002 07:52 AM

PHP Code:


		
			
//Drakks Warning Hack

$warnfield="field10" //make x the field for ur warning level

echo "warnfield=$warnfield <br>";

echo "bbuserinfo=$bbuserinfo<br>";



$warnlevel = $DB_site->query_first("SELECT $warnfield FROM userfield WHERE userid='$new_var_323'");

$warnlevel=$warnlevel[$warnfield];

in that case this is the line:

PHP Code:


		
			
echo "warnfield=$warnfield <br>";

if u get rid of that and the bit after it and this is in there this is the line:

PHP Code:


		
			
$new_var_323= $bbuserinfo[userid];

but.. if that aint there this is the line:

PHP Code:


		
			
$warnlevel = $DB_site->query_first("SELECT $warnfield FROM userfield WHERE $bbuserinfo[userid]");

and so on

E	04-02-2002 08:00 AM

o and the first line of this bit of code is the reference too the sessions.php

PHP Code:


		
			
  // get pertinient user info

  if (!isset($bbuserinfo) or $bbuserinfo['userid']!=$session['userid']) {

    $bbuserinfo=getuserinfo($session['userid']);

    $bbuserinfo['realstyleid'] = $bbuserinfo['styleid'];

  }

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