Randomly running some code
 

I have some ad code, but only want to show it with a 1 in 10 chance. The code is:

It will be in my postbit legacy template.

Is there any vbulletin code that allows me to do this?

Thanks,

Jon

I think this would work:

Basically, whenever the current time (in seconds) ends in 0 it will show.

Clever idea, thanks! I will try that. :)

--------------- Added [DATE]1382625240[/DATE] at [TIME]1382625240[/TIME] ---------------

Seems to work. :) Would be nice to work out how to vary the probability of display. e.g 1 in 7 or whatever. So, I could say decide to set it to 1 in 7 or 1 in 5 etc.

Switch the number (i.e. 10) after the % to whatever you want, so 1 in 7 change the 10 to a 7, 1 in 5 change the 10 to a 5.

Yeah, what squidsk said. I simplified the explanation a little, the code actually divides the unix time (seconds since Jan 1 1980 or something like that) by ten and checks that the remainder is 0, which happens when the last digit is 0 (since we're dividing by 10). But you can just as easily divide by 7 (or whatever) and check for a remainder of 0 to get a 1 in 7 chance.

I've tried using 2 and it showed my ads 1 in 2 chance. But when I tried 4 or 7, it didn't show 1 in 4 or 1 in 7 times. Maybe the maths is a bit out somehow? Do I need to clip off the decimals or something?

Hmm...'%' should divide integers and return the remainder, so I don't think decimals should matter. So you're saying condition="TIMENOW%7==0" doesn't work right?

I am trying 1 in 4 right now. TIMENOW%4==0

See it in action (or not as the case may be!):http://access-programmers.co.uk/foru...ar#post1301767

The third post has a 300x250 advert. There should be another one appearing to the right of that one 1 in 4 times. But it doesn't.

OK, I ran a test and it seems to work. Are you saying that the exact code works with 10 or 2 but not 4 or 7 (I guess I'm saying, are you sure there's not a typo)? If you do this (add the 1|| in the condition):

then it should show every time and you can make sure there's not something else wrong.

The only other thing I can think of is that it's not exactly random because it's based on the time, so if for example you have it set to 4 and you constantly hit reload, and the page happens to take about 4 seconds to load each time, you may end up with something that looks like it's not a 1 in 4 chance.

My code is:

I got it to show 2 out of 13 goes. Maybe I was just unlucky with my first few tries. I will try 1 in 3. :)