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singabaloo 10-02-2012 03:20 AM

SQL Query - format Date
 
I'm trying to run a MySQL query to list the members of a group and show the last activity date. The results gives me the date in a serial number like 1349148662

Here is my code. What do I need to add or change to format the query correctly ?

Code:

SELECT  `user`.`username` ,  `user`.`usergroupid` ,  `user`.`lastactivity`
FROM  `user`
WHERE (
`user`.`usergroupid` =  "7"
)
ORDER BY  `user`.`lastactivity` DESC
LIMIT 0 , 30


nerbert 10-02-2012 04:08 AM

What it's returning is the timestamp. You can use PHP to convert to the date format of your choice with date(format, timestamp)

http://www.w3schools.com/php/func_date_date.asp

I think there's a way to have MySQL do it but I forgot how it works

singabaloo 10-02-2012 04:44 AM

Thanks. I've found theMySql format but I can't seem to get it to display. I get no errors so I assume it's not massively wrong.

Code:

SELECT `user`.`username`, `user`.`usergroupid` , DATE_FORMAT(`user`.`lastactivity`, '%d/%m/%Y') as `date_string`
FROM `user`
WHERE (`user`.`usergroupid` ='7' OR `user`.`usergroupid` ='5')
ORDER BY `user`.`lastactivity` DESC

I want to try and keep it as MySQL code so I can add it to the queries.php and allow other admins to run the canned query.

--------------- Added [DATE]1349158474[/DATE] at [TIME]1349158474[/TIME] ---------------

OK, I got it working using the FROM_UNIXTIME function.

Code:

SELECT username, usergroupid , FROM_UNIXTIME(lastactivity) AS ladate
FROM user
WHERE (usergroupid ='7' OR usergroupid ='5')
ORDER BY ladate DESC


nerbert 10-02-2012 05:25 AM

I guess that isn't a timestamp, but is generated by the PHP time() function at the time of the update. What MySQL wants is a proper timestamp, which looks like this: 2008-11-11 12:45:34. I don't know how you would convert using MySQL

singabaloo 10-02-2012 05:35 AM

As above, using the FROM_UNIXTIME I was able to reformat the lastactivity time correctly.

Now to tackle getting a search from two separate tables working.


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