Current URL inside Hyperlink
 

I'm basically attempting to create a 'share to Twitter'-button. It uses this code:
Now I want the code to automatically insert the current URL (of the current thread) (replacing the www.website.com/postx).

Because I have vbSEO installed, I tried to use the variable $_SERVER[VBSEO_URI] (but also the original vBulletin variable http://$_SERVER[HTTP_HOST]$_SERVER[REQUEST_URI]). But apparently the link doesn't translate any of those variables into actual links. Maybe because the variable is placed inside the quotation marks.

Is there a way to have it properly translate the variable to a usable URL?

Try with this:
This will share the current post link and will be converted to vBSEo links as well.

I've included a image wich can be used with this post at 32px but you can use any image that you want.

- Rafael

That's great, thank you very much :)

I've also inserted the Thread Title into the tweet by adding the variable {vb:raw thread.title}. But the URL isn't converted into a vBSEO link, instead it just uses the 'normal' vBulletin links. Does vBSEO have its own variables that I could use?

Yes, vBSEO have it's own variables, take a look at here: http://www.vbseo.com/f2/vbseo-functi...sibility-1662/ so you can check the extensibility.