syntax problems with checking for constants in an array?
 

if ($user[membergroupids] == USERGROUP_A) always returns true, but
if ($user[membergroupids] == 'USERGROUP_A') and
if ($user[membergroupids] == " . USERGROUP_A . ") always returns false

If I just go
if ($user[membergroupids] == '2'), it works as it should.

Similarly, later on,

if ($groupid != USERGROUP_A) branches properly.

WTF am I doing wrong?

Have you tried $user['membergroupids'] ?

That doesn't seem to affect it.

Thanks, though.

$user[membergroupids] is a list of user groups separated by commas

you need to explode(',') it and get an array with a list of user group ids to work with

not sure if constants get parsed inside quotes, but this

if ($user[membergroupids] == " . USERGROUP_A . ")

should work I think O_o

Correct. I was actually trying to check for one (and only one) membergroup. If there were more than one, it branched and did something else.

That always returns as false. I'm not sure why.

There is no need to concencate the constant....You're not including any other bits of data.

still he's curious, as am I

Which will check primary & secondary usergroups for USERGROUP_A.

Are you referring to my post? If you are, you're not starting the string, so it'd error out.
That would work.

Why even add the empty strings around it though? is correct, but membergroupids is a comma separated list, so you need to either explode it, or use is_member_of().