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lightnb

05-25-2006 02:03 AM

Math Question

Code:

A = 2(TAN(F*F))

How do you re-write the formula to solve for F?

peterska2

05-25-2006 02:10 AM

so

A = 2(TAN(F Squared)

A = Tan(F squared) + Tan (F squared)

A/Tan = (f squared) + (f squared)

A/Tan = 2(f squared)

A/(2 Tan) = F squared

square root (A/(2 tan)) = F

Could be wrong, coz it's a long while since I last did algebra though.

Freesteyelz

05-25-2006 02:30 AM

*Sigh* I feel so inadequate. :lick:

Adrian Schneider

05-25-2006 02:44 AM

F = squareroot(inversetan(a/2);

My work:

Code:

a = 2tan(F*F);

a/2 = tan(F*F);

iTan(a/2) = F*F

2root(iTan(a/2)) = F;

Xenium

05-25-2006 10:00 AM

Me too.. F = SQUAREROOT(INVERSETAN(A/2))

@peterska2. The inverse of TAN is INVERSETAN not divide tan:p

Code:

A = 2(TAN(F*F))

A = 2(TAN(F^2))

A/2 = TAN(F^2)

INVERSETAN(A/2) = F^2

F = SQUAREROOT(INVERSETAN(a/2))

peterska2

05-25-2006 11:08 AM

I knew it was probably wrong, but it's a long while since I last did algebra.

lightnb

05-25-2006 11:28 AM

Thanks guys :)

I was never too good at algebra...

is inverse tangent the same as arc tangent?

in other words, would:

PHP Code:


		
			
$F = SQRT(atan($A/2));

be the correct PHP syntax for this?

Xenium

05-25-2006 02:13 PM

Yes. Arc tan is the inverse of tan for php.

But the return is in radians. So if you want it in degrees, you will need to use rad2deg.

E.G.

PHP Code:


		
			
$F = SQRT(rad2deg(atan($A/2)));

lightnb

05-25-2006 10:32 PM

$A should be in degrees. $f should be a decimal

who is chris c

05-25-2006 11:21 PM

just a fyi you cant divide normal trig fnct (sin, cos, tan) by both sides like normal you need to take the inverse (^-1) to do the equalitive property been awhile but thought i'd throw that in

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