vb.org Archive - Damn Classes /; (the php type)

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- - Damn Classes /; (the php type) (https://vborg.vbsupport.ru/showthread.php?t=102289)

pyro.699

12-05-2005 07:30 PM

Damn Classes /; (the php type)

ok, im working on a vb free site and im setting up a code so that inorder to write/read a query i need to only type

PHP Code:


		
			
$db->query();

now, here is what i hvae built so far!

PHP Code:


		
			
class Blizz { var $blizz; }



//set the function

    $this->connection = $resource;

    ($resource = mysql_connect());

 function query($query) 

{ 

    $resource = mysql_query($query, $this->connection); 

    if (!$resource) 

    { 

        $this->debug_query($query); 

    }



    return $resource;

}





$db = new Blizz($dbhost, $dbuser, $dbpass, $dbname);

ok,

PHP Code:


		
			
$dbhost

$dbuser

$dbpass

$dbname

are all defined above... in the part of the sript that you can't handle!

why isent this working? ill give you my current error:

Quote:

Originally Posted by PHP 5.0.4

Fatal error: Using $this when not in object context in C:\apachefriends\xampp\htdocs\blizz\connect.php on line 35

i dont know if this matters, but line #35 is

Quote:

Originally Posted by Notepad ++

$this->connection = $resource;

anyways, i would ask AJ but, i feel like ive bugged him enough ^^;

Ty in advance
~Cody Woolaver

Guest190829

12-05-2005 07:40 PM

$this should only be used inside methods AFAIK...

*I'm still very new to OOP*

pyro.699

12-05-2005 07:43 PM

Im new aswell ^^

umm, so, where what should i put it inside of?

Guest190829

12-05-2005 08:02 PM

Well that function isn't even in your class, you're defining a class with no methods in it. I don't know if the below will work as I haven't tested it....nor am I an OOP guru, as I am still learning myself.

PHP Code:


		
			
var $resource =mysql_connect();



class Blizz { 



//set the function

    

 function query($query) 

{ 

    $this->connection = $resource;

    $this->resource = mysql_query($query, $this->connection); 

    if (!$this->resource) 

    { 

        $this->debug_query($query); 

    }



    return $this->resource;

}





$db = new Blizz;

$query = $db->query("QUERY");

And also what do you mean by a vb free site?

pyro.699

12-05-2005 08:09 PM

Update of code:

PHP Code:


		
			
class Blizz { var $blizz;

         var $resource = mysql_connect(); }



//set the function

    $this->connection = $resource;

    ($resource = mysql_connect());

 function query($query) 

{ 

    $resource = mysql_query($query, $this->connection); 

    if (!$resource) 

    { 

        $this->debug_query($query); 

    }



    return $resource;

}





//Connect

$db = new Blizz($dbhost, $dbuser, $dbpass, $dbname);

Quote:

Originally Posted by PHP 5.0.4

Parse error: parse error, expecting `','' or `';'' in C:\apachefriends\xampp\htdocs\blizz\connect.php on line 34

Line 34

Quote:

Originally Posted by Notepad ++

var $resource = mysql_connect(); }

Guest190829

12-05-2005 08:12 PM

Your closing the class before defining any methods, you have to wrap the closing bracket "}" at the end of all you methods.

pyro.699

12-05-2005 08:27 PM

yeah, i had a feeling that was an answer
Updated Script

PHP Code:


		
			
class Blizz { var $blizz;

            var $resource = mysql_connect();



//set the function

        $this->connection = $resource;

        ($resource = mysql_connect());

    function query($query) 

    { 

        $resource = mysql_query($query, $this->connection); 

        if (!$resource) 

        { 

            $this->debug_query($query); 

        }



        return $resource;

    }

}



//Connect

$db = new Blizz($dbhost, $dbuser, $dbpass, $dbname);

Quote:

Originally Posted by PHP 5.0.4

Parse error: parse error, expecting `','' or `';'' in C:\apachefriends\xampp\htdocs\php_testing\blizz\co nnect.php on line 28

Line 28:

Quote:

Originally Posted by Notepad ++

var $resource = mysql_connect();

AN-net

12-05-2005 09:14 PM

you can not run a function or set a var when initialzing it, except for setting it as an array. if you want to set that var as mysql_connect create a constructor function at the beginning of your class.

The Geek

12-05-2005 09:20 PM

Just to build on AN-nets excellent pointer:

PHP Code:


		
			
class myclass
{
 
var myvariable;
 
function myclass($var)
{
//your constructor is a function with the same name as your class
$this->myvariable = $var;
}
}

HTH's

pyro.699

12-05-2005 09:26 PM

so, after that, is there anyhting else i need to do? or did i have a whole bunch of shit in mine that wsent neded?

----
ok, scrap what i just said

i am completely lost, can you guys amke me an example? that fully works!

i want to type

PHP Code:


		
			
$db->blizz->query("QUERY");

and for that query to be ran

you should see all the backup files ive made for this project.. lol.. ig to about 20... and none of em work! i just need this made, idc how much space it takes! i really need this ;) it will save me a lot of time!

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