Randomly running some code
 

I have some ad code, but only want to show it with a 1 in 10 chance. The code is:

It will be in my postbit legacy template.

Is there any vbulletin code that allows me to do this?

Thanks,

Jon

I think this would work:

Basically, whenever the current time (in seconds) ends in 0 it will show.

Clever idea, thanks! I will try that. :)

--------------- Added [DATE]1382625240[/DATE] at [TIME]1382625240[/TIME] ---------------

Seems to work. :) Would be nice to work out how to vary the probability of display. e.g 1 in 7 or whatever. So, I could say decide to set it to 1 in 7 or 1 in 5 etc.

Switch the number (i.e. 10) after the % to whatever you want, so 1 in 7 change the 10 to a 7, 1 in 5 change the 10 to a 5.

Yeah, what squidsk said. I simplified the explanation a little, the code actually divides the unix time (seconds since Jan 1 1980 or something like that) by ten and checks that the remainder is 0, which happens when the last digit is 0 (since we're dividing by 10). But you can just as easily divide by 7 (or whatever) and check for a remainder of 0 to get a 1 in 7 chance.

I've tried using 2 and it showed my ads 1 in 2 chance. But when I tried 4 or 7, it didn't show 1 in 4 or 1 in 7 times. Maybe the maths is a bit out somehow? Do I need to clip off the decimals or something?

Hmm...'%' should divide integers and return the remainder, so I don't think decimals should matter. So you're saying condition="TIMENOW%7==0" doesn't work right?

I am trying 1 in 4 right now. TIMENOW%4==0

See it in action (or not as the case may be!):http://access-programmers.co.uk/foru...ar#post1301767

The third post has a 300x250 advert. There should be another one appearing to the right of that one 1 in 4 times. But it doesn't.

OK, I ran a test and it seems to work. Are you saying that the exact code works with 10 or 2 but not 4 or 7 (I guess I'm saying, are you sure there's not a typo)? If you do this (add the 1|| in the condition):

then it should show every time and you can make sure there's not something else wrong.

The only other thing I can think of is that it's not exactly random because it's based on the time, so if for example you have it set to 4 and you constantly hit reload, and the page happens to take about 4 seconds to load each time, you may end up with something that looks like it's not a 1 in 4 chance.

My code is:

I got it to show 2 out of 13 goes. Maybe I was just unlucky with my first few tries. I will try 1 in 3. :)

Well, if I view the html source of the page you linked to above, and search for 'data-zone="ron" data-format="300x250"', I find it once, but occasionally I'll find it twice. So it kind of seems to me like it might be working, but I don't see any ads at all on that page.

Edit: Also (possibly related), when I look at the JS console I see this:

Something doesn't seem quite right. For 1 in 3, I am now at 9 out of 13.

OK, well maybe there's something about the way it works that I don't understand. Anyway, here's another one you can try:

That one doesn't work too well for me because strangely some of the digits of what's supposed to be the current time with microseconds don't change from one page to another. But apparently it's OS dependent and I'm running on my home Windows 7 computer, so it might work better for you.

Edit:...otherwise, it's not too difficult to write a plugin that does an actual random number.

How do I reverse the condition?

I have an advert showing if condition=x. But I want to stop showing an advert in another location is condition=x. So, what is the reverse?

Edit:Worked it out. Use != instead of ==