vb.org Archive - ## Little PHP Assistance ##

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- - ## Little PHP Assistance ## (https://vborg.vbsupport.ru/showthread.php?t=103491)

Marco van Herwaarden

12-23-2005 08:11 AM

[sql]SELECT username FROM user ORDER BY posts DESC LIMIT 1;[/sql]

Mr Chad

12-24-2005 12:57 AM

never mind did it ^^

PHP Code:


		
			
//get latest ecdownload

$queryf= "SELECT name AS newdownload FROM " . $TABLE_PREFIX . "dl_files ORDER BY id DESC LIMIT 1"; 

$latestdownloada = mysql_query_eval($queryf,$link);

$latestdownloadb = mysql_fetch_array($latestdownloada);

$latestdownload= $latestdownloadb['newdownload'];

mysql_free_result($latestdownloada);

Is there a way to get currently online? only useing the database?

PHP Code:


		
			
//get total online

$queryh= "SELECT COUNT(*) AS online FROM " . $TABLE_PREFIX . "session"; 

$onlinea = mysql_query_eval($queryh,$link);

$onlineb = mysql_fetch_array($onlinea);

$online= number_format($onlineb['online']);

mysql_free_result($onlinea);

it gets a huge number... any way to fix this?

anyone?

Marco van Herwaarden

12-24-2005 07:50 AM

You will have to limit to the rows with a dateline later then the current time minus cookie timeout.

Mr Chad

12-24-2005 05:32 PM

Quote:

Originally Posted by MarcoH64

You will have to limit to the rows with a dateline later then the current time minus cookie timeout.

wow, im over my head.

Marco van Herwaarden

12-24-2005 07:50 PM

To put it more simple. Rows are added to the session table all the time. The table gets cleaned again once an hour (i think by default) by a scheduled task.

A user is 'online' however if his last action (page load) was less the the cookie timeout ago. So if the cookie timeout is set to 900 (seconds, 15 minutes, default), then you only want to rows from the session table of the last 900 seconds.

Mr Chad

12-24-2005 10:30 PM

yea but the time it shows in the table is a huge number like 8 digits

How would i make it just count the rows with userid > 0

Marco van Herwaarden

12-25-2005 07:31 AM

PHP Code:


		
			
$queryh= "SELECT COUNT(*) AS online FROM " . $TABLE_PREFIX . "session WHERE userid > 0 AND lastactivity > " . (TIMENOW - $vbulletin->options['cookietimeout'])";

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