PHPInclude End help

[Michael Morris]

I can't get the following query to work in the PHPINCLUDE_END template, and can't figure out why..

if ($foruminfo['id']=='158')
{
$output = str_replace("images/icons/", "http://www.enworld.org/forums/images/swtemp/", $output);
}

I know the strreplace works, it's the conditional that's not working...

[Xenon]

its
if ($foruminfo['forumid'] == 158)
{
$output = str_replace("images/icons/", "http://www.enworld.org/forums/images/swtemp/", $output);
}

:)

[Michael Morris]

Doesn't work :(

[miz]

can be also

if ($forum['forumid'] == 158)
{
$output = str_replace("images/icons/", "http://www.enworld.org/forums/images/swtemp/", $output);
}

[Michael Morris]

Nope, that don't work either... :(

[Dean C]

Put it in the phpinclude_start template :)

[Michael Morris]

I would, but I can't execute a string replace until the output is compiled. PHPINCLUDE_START parses too early for that.

I tried putting it into phpinclude_start and setting a flag variable to true, but THAT didn't work. For some reason PHPINCLUDE_END won't evualtes all variable checks to false unless they're constants..

I haven't tried defining a constant in the PHPINCLUDE_START template yet.

[Xenon]

hmm, , try that code maybe:


global $foruminfo;
if ($foruminfo['forumid'] == 158)
{
$output = str_replace("images/icons/", "http://www.enworld.org/forums/images/swtemp/", $output);
}

but changing the output in phpinclude_end might not be possible at all, so it might not be the condition ;)

[Michael Morris]

Heh heh, it's possible - I've tested the query by itself without the conditional. I'll try the global call and see if that helps. Thanks :)