View Full Version : Remove status icons..
DiMoNd21
02-03-2007, 09:09 AM
Hi! I am trying to find the template to edit to remove the status icons from the bottom of my forum.Those right over footer.
http://img112.imageshack.us/img112/2446/imagemb1.png
CyberAlien
02-03-2007, 09:12 AM
In forumhome replace this:<!-- icons and login code -->
<table cellpadding="0" cellspacing="2" border="0" width="100%">
<tr valign="bottom">
<td>
<table cellpadding="2" cellspacing="0" border="0">
<tr>
<td><img src="$stylevar[imgdir_statusicon]/forum_new.gif" alt="$vbphrase[contains_new_posts]" border="0" /></td>
<td class="smallfont"> $vbphrase[forum_contains_new_posts]</td>
</tr>
<tr>
<td><img src="$stylevar[imgdir_statusicon]/forum_old.gif" alt="$vbphrase[contains_no_new_posts]" border="0" /></td>
<td class="smallfont"> $vbphrase[forum_contains_no_new_posts]</td>
</tr>
<tr>
<td><img src="$stylevar[imgdir_statusicon]/forum_old_lock.gif" alt="$vbphrase[a_closed_forum]" border="0" /></td>
<td class="smallfont"> $vbphrase[forum_is_closed_for_posting]</td>
</tr>
</table>
</td>
<if condition="!$show['guest']">
<!-- member logout -->
<td align="$stylevar[right]"><a href="login.php?$session[sessionurl]do=logout&logouthash=$bbuserinfo[logouthash]" onclick="return log_out()"><phrase 1="$bbuserinfo[username]">$vbphrase[log_out_x]</phrase></a></td>
<!-- end member logout -->
</if>
</tr>
</table>
<!-- / icons and login code -->
with this:<if condition="!$show['guest']">
<table cellpadding="0" cellspacing="2" border="0" width="100%">
<tr valign="bottom">
<!-- member logout -->
<td align="$stylevar[right]"><a href="login.php?$session[sessionurl]do=logout&logouthash=$bbuserinfo[logouthash]" onclick="return log_out()"><phrase 1="$bbuserinfo[username]">$vbphrase[log_out_x]</phrase></a></td>
<!-- end member logout -->
</tr>
</table>
</if>
DiMoNd21
02-03-2007, 09:45 AM
Perfect!!Thank you very much!!:up:
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